Can someone explain how to do this question I just tried it and it's wrong.
A second method by which ethanoic acid is synthesised involves the oxidative
fermentation of ethanol in the presence of bacteria. The equation representing this
reaction is given below.
C2H5OH + O2 ----> CH3COOH + H2O
In a small scale experiment using this second method it was found that 23.0 g of ethanol produced only 4.54 g of ethanoic acid. Calculate the percentage yield for this experiment.
Percentage Yield Help Watch
- Thread Starter
- 17-04-2013 00:55
- 17-04-2013 01:15
I'll help get you started.
percentage yield = (actual mass of product) ÷ (theoretical mass of product) × 100
- 17-04-2013 02:49
I find it easier to work in terms of moles.
Find the moles of the limiting reagent (do you understand what I mean by this?) - in this case it will be the ethanol, as it is assumed there is plenty of oxygen!
Calculate the number of moles of the limiting reagent (ethanol).
Calculate the number of moles of product.
Work out the maximum possible number of moles of product, using the stoichiometery of the reaction. In this case it is 1:1.
Express as a percentage.