1. Use the factor theorem to factorise completely f(x)= x³+x²-4x-4.
Hence solve the equation x³+x²-4x-4=0
f(x) = x³ + x² - 4x - 4
f(x) = (x³ + x²) - (4x + 4)
f(x) = x²(x + 1) - 4(x + 1)
f(x) = (x + 1)(x² - 4)
f(x) = (x + 1)(x² - 2²)
f(x) = (x + 1)(x + 2)(x - 2)
x³ + x² - 4x - 4 = 0
(x + 1)(x + 2)(x - 2) = 0
Hi people I did start a thread yesterday on this, it seems the way I approached factor theorum yesterday was wrong so I've gone away and had a bash at it again can someone please let me know if I am now correct?
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sunny1982
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- 17-04-2013 11:28
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- 17-04-2013 11:31
that's just factorising. the factor theorem is the remainder theorem and you sub in until you get 0. factorising like this is much better
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ghostwalker
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- 17-04-2013 11:31
(Original post by sunny1982)
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- 17-04-2013 11:34
Well you haven't actually used the factor theorem.
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