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# ISA question is seriously screwing me over watch

1. Graph of log10T plotted against log10d

Q: Theory that T=k/d
Discuss whether the value of G supports this theory

A : T=kd^-1
and that the power of d is equal to the gradient.

Problem is, I don't see how this answer supports the theory whatsoever.
So if someone could shed some light on this?
2. If T=k/d

then taking logs gives

Log T = Log k - Log d

A graph of Log T against log d would have a gradient of -1 with Log k as the intercept.

(Log T) = (-1)(Log d) + (Log k)
(Y) = (m) (x) + (c)
3. Thanks, that clears it up.

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