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    Hi, this question is right doing my head in. (Just part iii)

    Solution please anyone


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    (Original post by _JC95)
    Hi, this question is right doing my head in. (Just part iii)

    Solution please anyone


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    Set \ y = y \Rightarrow   6 \times 5^x = 9^x Then take \log_3 of both sides.
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    (Original post by joostan)
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    Set \ y = y \Rightarrow   6 \times 5^x = 9^x Then take \log_3 of both sides.
    yeah I've already done that, I'm treating it exactly as I would a usual logarithm equation, but I just can't seem to get it in terms of x...
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    nevermind i've done it now, a very awful mistake early on haha


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    What specification is this?
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    (Original post by Alex-Torres)
    What specification is this?
    OCR
 
 
 
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