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    Well I am starting the circle theorems, for my retakes for GCSE maths higher, anyways can anyone help me do this question? They are starting to get harder when I am moving to the the A-work (from the big collins edxcel book) so I may ask more questions later but can you try and help me understand how to do this one?

    Thanks.
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    well the 61 degress bit the opposite side to that one is also 61 degress since same length sides which is alternate angles in same segment then you do 95 + 61 = 156 degress and to find x = 180 - 156 = 24 degress for the right triangle and same for other side = 360 degress

    Done circle theorms in higher exam
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    (Original post by Xmarksthesh0t)
    Well I am starting the circle theorems, for my retakes for GCSE maths higher, anyways can anyone help me do this question? They are starting to get harder when I am moving to the the A-work (from the big collins edxcel book) so I may ask more questions later but can you try and help me understand how to do this one?

    Thanks.
    I'll label the points ABCD going anticlockwise from the angle marked x.
    Then angle BCA = angle BDA because they're angles from a chord. Does that help?
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    The theorm for this circle i have realised is alternate angles in same segment which means they are the same on both sides basically. This is one of the easy forms of this question if ur doing the modular edexcel higher they get harder in unit 3 which is what im doing in june :/

    Why give me bad feedback just because im right
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    (Original post by Smaug123)
    I'll label the points ABCD going anticlockwise from the angle marked x.
    Then angle BCA = angle BDA because they're angles from a chord. Does that help?
    I get you guys, but I'd much rather a illustration, to help me understand where the alternate is, if that is possible, thanks.

    On second thought, now I understand it thanks .
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    i will get a image
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    This is a pic of the alternate segment which is exactly this one
    the 2 in the triangle are the same since both in same triangle lol
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