2 particles collide completely inelastically
Particle A has mass m and momentum 2p.
Particle B has mass 2m and momentum p.
Initial kinetic energy is calculated as (3p^2)/(4m)
Momentum is conserved in competely inelastic collisions, whereas kinetic energy is not conserved here.
Thus, p(initial) = p(final)
Thus, (3p^2)/(4m) = p(final)
Total mass of system = m + 2m = 3m
Total momentum of system (using addition of vectors & Pythagors) = sqrt of (p)^2 + (2p)^2]
= sqrt of [p^2 + 4p^2]
= sqrt of 5p^2
= (sqrt of 5)*p
This momentum is the same before and after the inelastic collision.
to work out final kinetic energy, I use 0.5mv^2 = (0.5P^2)/M where the mass M and momentum P here are respectively the TOTAL mass and TOTAL momentum of the SYSTEM
M = 3m, so final KE = [0.5*(5p)^2]/(3m)
Where has this gone wrong?
2 particles are in a completely inelastic collision, calculate final Kinetic Energy? Watch
- Thread Starter
- 19-04-2013 08:03
- 19-04-2013 09:26
- Study Helper
- 19-04-2013 10:01
0.5mv^2 = (0.5P^2)/M ??????