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    I'm having trouble with question 10, I've integrated but can't seem to simplify it to get the answer required. Any help would be much appreciated
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    (Original post by candyhearts)
    I'm having trouble with question 10, I've integrated but can't seem to simplify it to get the answer required. Any help would be much appreciated
    Try grouping the fractions together and then take out a factor of (1+\sin x)^6. (Your last line is wrong).

    You may find it easier to simplify the fractions and then factorise before making the substitution for u.
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    (Original post by notnek)
    Try grouping the fractions together and then take out a factor of (1+\sin x)^6. (Your last line is wrong).

    You may find it easier to simplify the fractions and then factorise before making the substitution for u.
    By the last line being wrong, do you mean it should be over 42? Also, what do you mean by simplifying the fractions before making the substitution? Thanks for your help
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    You are correct up to the second from last line.
    To get the expression into the given form just factorise out  1/42 *(sinx +1)^6
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    so:

    1/7*(sinx +1)^7-1/6*(1+sinx)^6 becomes:

    1/42*(1+sinx)^6(6(1+sinx)-7)

    This is done by spotting the common factor which makes the solution look a bit nicer.
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    (Original post by jassi1)
    so:

    1/7*(sinx +1)^7-1/6*(1+sinx)^6 becomes:

    1/42*(1+sinx)^6(6(1+sinx)-7)

    This is done by spotting the common factor which makes the solution look a bit nicer.
    Ah that makes sense now, thank you
 
 
 
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