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S1 Edexcel 2003 Exam Answers watch


    I meant question 2, the normal distribution. What did everyone get t as?
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    i got like between 14 and 15....14.42 something like that....

    basically i looked up 20% in the percentage table thingy...

    I got 9.45 hours
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    Originally posted by Unregistered
    I got 9.45 hours
    Urrr... 9.45 is less than the mean is it not (I can't remember exactly that the mean for the distribution was)? If it is less than the mean, then it can't be the correct answer. P(X > mean) = 0.5, so P(X > mean - c) for c positive is going to be greater than 0.5, which does not allow the value given by the question of 0.2 (1 in 5).

    Regards,

    So what did you get?
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    Originally posted by Unregistered
    So what did you get?
    I can't remember exactly but I think it was 14. something or 15. something.

    Does anyone remember what the mean and s.d. were for the distribution? Then I can work it out again and post the correct answer.

    Regards,

    mean=12
    sd=3

    For Z i got -0.85
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    Originally posted by Unregistered
    mean=12
    sd=3
    So X follows N(12, 3^2). Z follows N(0, 1)

    P(X > c) = 0.2
    P(Z > (c - 12)/3) = 0.2
    1 - P(Z < (c - 12)/3) = 0.2
    P(Z < (c - 12)/3) = 0.8
    So (c - 12)/3 = 0.84 (using big table for psi(z) = 0.7995 (closest))
    Therefore c = 14.52

    If you were to use the table over the page, which gives an exact value for 1 - psi(z) in our case, you can be more accurate and say:

    P(X > c) = 0.2
    P(Z > (c - 12)/3) = 0.2
    (c - 12)/3 = 0.8416
    Therefore c = 14.5248

    The difference, as you can see, is almost negligible, and our teachers tell us that it doesn't matter which table you use.

    Regards,

    Now i c where i went wrong, I added in a minus!!
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    Does anyone know how many marks the last question was worth in total, and which was the explanatory variable?

    What was the total mark for the exam?

    I didn't see question 7, and only did part (a) and a section of part (c) calculating B - how many marks will I pick up for this?

    How many points do you need in the exam for an A/B/C/D etc?

    i thought Q2 was hard. i did 1- probabilty of 0.8 so i got like 12.48,
    I am pretty sure the explanatory variable was maths, since i read in my book explanatory = independant variable, i.e. variable that you change.
    apart from that test was alright, too many graphs though i spent half the time drawing them. hope to get over 80%
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    I got the same least squares regression line as some of you guys but my regression line was properly screwed !!!!
    Any ideas ???(I think my y axis was M and my x axis was P if anyone did the same)

    My answer for question 2 was 14.5(3.s.f) by the way.

    Hello dudes. Just done the people just done the S1 paper again. Lifted a copy from school. These are the answers I got.

    1.
    Easy histogram (with class boundaries between i.e 7.5~8.5)
    2.
    I got t = 14.52 for life of battery
    3a)
    Sxy = -157.86
    Sxx = 155.92
    Syy = 214.96

    3b)
    PMCC= -0.862 to 3sf

    3ci) PMCC unaffected by coding
    cii) Strong negative correlation

    4a) Proved k = 1/50
    b) E(x) = 5.4
    Var(x) = 0.52

    4c) Var(2x-3) = 4Var(x) = 2.08

    5 Dice
    a) Uniform Distribution
    b)E(x) = 3.5
    Var(x) = 35/12
    c) P(6,6,6) = 1/216
    d)Score 16
    6,6,4 6,4,6 4,6,6 5,5,6 5,6,5 6,5,5

    So P(16) = 6/216 = 1/36

    6a) Mean = 22 and 2/7
    b) Unordered then ordered Stem & Leaf
    c) Median = 20 , LQ = 13 , UQ = 31
    d) IQR = 18 So no outliers
    e) Box Whisker
    f) Q2-Q1<Q3-Q2 so positive skew

    7a) M explanatory
    b) Scatter
    c) Regression Line: 2.23 + 1.41x
    d) Line best fit
    e) Approx 23 in Physics if student got 15 in maths

    Did everyone else get these or similar?:

    Forgive me if there are any mistakes but I thought I would post somke solutions to put people out of their misery. Hope it went well dudes.
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    Originally posted by Unregistered
    Hello dudes. Just done the people just done the S1 paper again. Lifted a copy from school. These are the answers I got.

    1.
    Easy histogram (with class boundaries between i.e 7.5~8.5)
    2.
    I got t = 14.52 for life of battery
    3a)
    Sxy = -157.86
    Sxx = 155.92
    Syy = 214.96

    3b)
    PMCC= -0.862 to 3sf

    3ci) PMCC unaffected by coding
    cii) Strong negative correlation

    4a) Proved k = 1/50
    b) E(x) = 5.4
    Var(x) = 0.52

    4c) Var(2x-3) = 4Var(x) = 2.08

    5 Dice
    a) Uniform Distribution
    b)E(x) = 3.5
    Var(x) = 35/12
    c) P(6,6,6) = 1/216
    d)Score 16
    6,6,4 6,4,6 4,6,6 5,5,6 5,6,5 6,5,5

    So P(16) = 6/216 = 1/36

    6a) Mean = 22 and 2/7
    b) Unordered then ordered Stem & Leaf
    c) Median = 20 , LQ = 13 , UQ = 31
    d) IQR = 18 So no outliers
    e) Box Whisker
    f) Q2-Q1<Q3-Q2 so positive skew

    7a) M explanatory
    b) Scatter
    c) Regression Line: 2.23 + 1.41x
    d) Line best fit
    e) Approx 23 in Physics if student got 15 in maths

    Did everyone else get these or similar?:

    Forgive me if there are any mistakes but I thought I would post somke solutions to put people out of their misery. Hope it went well dudes.

    **** looking at it now, I did a number of mistakes.
    -----------------------------------------------------------------
    1) f) Q2-Q1<Q3-Q2 so positive skew

    Here I put negative skew
    ----------------------------------------------------------------
    2) I got t = 14.52 for life of battery
    And this one I got wrong... Wasn't the question saying that 4/5 of batteries selected should have a higher average life...? Shouldn't that mean that you should get a value that translates to a negative value in the normal distribution, so that 4/5 of the area is after it?
    -----------------------------------------------------------------
    3) Score 16
    6,6,4 6,4,6 4,6,6 5,5,6 5,6,5 6,5,5

    So P(16) = 6/216 = 1/36
    I only found 5 combinations here...
    -----------------------------------------------------------------
    4) The histogram I ****ed up and did very hastily... I left it to the end, and I drew it wrong, one of the bars was 0.5 units wider (in fact I noticed it before the exam was over but since I didn't have enough time to finish, I actually wrote "this width is wrong by 0.5 units"
    -----------------------------------------------------------------
    5) Finally on the box plot, if the left wisker goes to below the mnimum value do you have to draw the whicker all the way to the end? For example here the lower boundary was -something, but the lowest value was 5... do we have to draw the whisker all the way to -something? Cause I only did it up to 5... doing bothe whiskers at the same length would pretty much ruin some of the predictive ability of the plot right? Or if I'm wrong I lost even more marks...

    Well that's all my mistakes I think... Is there a chance I might miss the A?

    I FLOPED due to lack of revision...gonna work hard on other 2 moduels

    u couldnt scan in the paper could you?

    Wish I could help but no scanner. Happy to type out a few questions if you have any specific ones in mind. Hope this helps, all the best, Dan
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    If you could post the mark allocations for each question part (ie 6,a,b,c) that would be great!

    6a 2
    b 3
    c 3
    d 3
    e 3
    f 2

    Hope this helps fella, cheers, Dan
 
 
 
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