The Student Room Group

nucleophilic substitution

http://www.google.com/url?sa=t&rct=j&q=january%202010%20question%20paper%20f332%20ocr&source=web&cd=1&ved=0CCwQFjAA&url=http%3A%2F%2Fwww.ocr.org.uk%2Fimages%2F57915-question-paper-unit-f332-chemistry-of-natural-resources.pdf&ei=3NtyUcaBAcvWPPKygbAK&usg=AFQjCNErxQWwNPmE9RLVXjjg1wS_9KLqNA&sig2=JyPddmoDoYvqiUB5RwRtLg&bvm=bv.45512109,d.d2k

I need help on question 2bii. The answer is nucleophilic and substitution, but why? The Br-H molecule is polarised with bromine having a slightly negative charge and hydrogen having a slightly positive charge. In the methanol molecule's C-O bond, the C is sightly positively charges and the O is slightly negatively charged. So the Br in Br-H is attracted to the C in methanol while the O is repelled. So bromine joins onto carbon O-H goes off and reacts with hydrogen to make water, forming bromomethanol. Is this a right explanation

Btw, why can't the substitution be electrophilic? Is it because there's no double bonds in methanol, so there is not a region of very high electron density,
Seems right to me! Electrophilic addition is all about the addition of a halogen into the compound I think because of the whole "rich in electron density" I think, sorry I'm not too confident about organic chemistry :smile:
Reply 2
Original post by krisshP
http://www.google.com/url?sa=t&rct=j&q=january%202010%20question%20paper%20f332%20ocr&source=web&cd=1&ved=0CCwQFjAA&url=http%3A%2F%2Fwww.ocr.org.uk%2Fimages%2F57915-question-paper-unit-f332-chemistry-of-natural-resources.pdf&ei=3NtyUcaBAcvWPPKygbAK&usg=AFQjCNErxQWwNPmE9RLVXjjg1wS_9KLqNA&sig2=JyPddmoDoYvqiUB5RwRtLg&bvm=bv.45512109,d.d2k

I need help on question 2bii. The answer is nucleophilic and substitution, but why? The Br-H molecule is polarised with bromine having a slightly negative charge and hydrogen having a slightly positive charge. In the methanol molecule's C-O bond, the C is sightly positively charges and the O is slightly negatively charged. So the Br in Br-H is attracted to the C in methanol while the O is repelled. So bromine joins onto carbon O-H goes off and reacts with hydrogen to make water, forming bromomethanol. Is this a right explanation

Btw, why can't the substitution be electrophilic? Is it because there's no double bonds in methanol, so there is not a region of very high electron density,


HBr is a strong acid (it's similar to HCl, but actually stronger). So it dissociates in polar solvents, and your alcohol is protonated by the H+ produced by HBr. This forms R-OH2+, which has a positively charged leaving group. Then the Br- attacks the carbon, substituting for water.

The reaction does not occur until the alcohol is protonated.

It is nucleophilic substitution because the bromine is acting as a nucleophile, and it is a substitution reaction.
Reply 3
Original post by VK96
http://chemwiki.ucdavis.edu/Organic_Chemistry/Reactions/E1_Reaction/Carbocation_Rearrangements
look there and go down to the hydride shift, it explains it in steps. See if that helps.
It uses a more complicated molecule but try to apply what it says to a methanol molecule.


Hydride shift is not relevant in this case because there is only 1 carbon, and the reaction is SN2 not SN1.
Reply 4
Original post by illusionz
Hydride shift is not relevant in this case because there is only 1 carbon, and the reaction is SN2 not SN1.

Ah I see, sorry about that :P
Reply 5
I kinda get it now after reading
http://www.chemguide.co.uk/mechanisms/nucsub/whatis.html#top

But how would I know just from an equation if there's electrophilic addition or nucleophilic substitution? Do I just see if there's a double bond for between carbons or what?
Reply 6
Original post by krisshP
I kinda get it now after reading
http://www.chemguide.co.uk/mechanisms/nucsub/whatis.html#top

But how would I know just from an equation if there's electrophilic addition or nucleophilic substitution? Do I just see if there's a double bond for between carbons or what?


Basically you just need to know the mechanism of the reaction. You can't tell from the equation.
Reply 7
Original post by illusionz
Basically you just need to know the mechanism of the reaction. You can't tell from the equation.



Original post by VK96
Ah


Thanks for the help :smile:

Quick Reply

Latest