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    There's a couple of questions on the EDEXCEL JUNE 2003 PURE 2 paper I cannot do. Does anyone happen to know where I could find solutions for this paper? Thanks a lot.
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    Why not post the problem here? The forum has many superb maths brains about. And I'd give it a go myself.
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    (Original post by XTinaA)
    Why not post the problem here? The forum has many superb maths brains about. And I'd give it a go myself.
    you do m2? check my m2 post! cheers !
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    (Original post by kikzen)
    you do m2? check my m2 post! cheers !
    Err this is P2 and I did M1, I chose S2 instead of M2 for my further maths AS...

    I'll have a look.
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    Umm, well it's one with a graph in...so I can't really show it. But if you go to http://www.mrhughes.net/Maths/Hidden%20Pages/login.htm username-alevel password-mrhughes. The paper's on there.

    I need help with 6 and 7. Thanks for your time!
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    (Original post by AATTMM)
    Umm, well it's one with a graph in...so I can't really show it. But if you go to http://www.mrhughes.net/Maths/Hidden%20Pages/login.htm username-alevel password-mrhughes. The paper's on there.

    I need help with 6 and 7. Thanks for your time!
    I've printed the questions you asked for and am looking at them, mind if I get it done tomorrow? I'll have a go now anyway...
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    Sure ^_^.

    6

    a) dy/dx = -c/x²

    when x = p, dy/dx = -4 => 4 = c/p² => c = 4p²

    b) 5 = 1 + (4p²)/p => 4=4p => p=1 => c=4.

    c) V = pi.integral[1,2] (1+4/x)² dx

    =pi.integral[1,2](1 + 8/x + 16/x²)dx

    =pi.[x + 8ln(x) - 16/x][1,2]

    =pi.[2-1 +8ln(2) - 8 + 16]

    =pi.(9 + 8 ln(2))

    => k = 9, q = 8.
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    7a) At M:
    x=0, y=7
    dy/dx = 2e^x = 2 so the gradient of the normal is -0.5
    => y-7=-0.5(x-0)
    2y-14 = -x
    2y+x=14

    7b) At N, y=0 so 2y+x=14 => x=14
 
 
 

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