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m1 help

how does

gtg=dg\frac{\sqrt g \sqrt t}{g}=\sqrt \frac{d}{g}

thanks :smile:
Original post by upthegunners
how does

gtg=dg\frac{\sqrt g \sqrt t}{g}=\sqrt \frac{d}{g}

thanks :smile:


Hopefully the root g in the denominator on the right is obvious.

As to the t becoming d, without some context, I'd suspect a typo.
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upthegunners
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Original post by ghostwalker
Hopefully the root g in the denominator on the right is obvious.

As to the t becoming d, without some context, I'd suspect a typo.

ahh yea I see :smile: thanks bro :smile:

what about this:

0=gd×t−12g×t20=\sqrt gd \times t - \frac{1}{2}g \times t^2

to 0=gt(2d−g×t)0= \sqrt g t(2\sqrt d - \sqrt g \times t)

thanks man :smile:
Original post by upthegunners
ahh yea I see :smile: thanks bro :smile:

what about this:

0=gd×t−12g×t20=\sqrt gd \times t - \frac{1}{2}g \times t^2

to 0=gt(2d−g×t)0= \sqrt g t(2\sqrt d - \sqrt g \times t)

thanks man :smile:


In the first equation, is the d meant to be under the square root sign?
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upthegunners
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Original post by ghostwalker
In the first equation, is the d meant to be under the square root sign?

yea it is :smile: thanks
Original post by upthegunners
ahh yea I see :smile: thanks bro :smile:

what about this:

0=gd×t−12g×t20=\sqrt{gd} \times t - \frac{1}{2}g \times t^2

to 0=gt(2d−g×t)0= \sqrt g t(2\sqrt d - \sqrt g \times t)

thanks man :smile:


OK, corrected that, you just need {} round whatever comes under the sign.

So, what bit's causing the problem?
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upthegunners
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Original post by ghostwalker
OK, corrected that, you just need {} round whatever comes under the sign.

So, what bit's causing the problem?

thanks :smile:

i can do it all but I am not sure where that 2 has come from? :s-smilie: in the brackets.
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upthegunners
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Original post by ghostwalker
OK, corrected that, you just need {} round whatever comes under the sign.

So, what bit's causing the problem?

do the multiply the expression by 2 then factor?
Original post by upthegunners
do the multiply the expression by 2 then factor?


Since you're dealing with multiplication and division, it doesn't matter which order you do it in.
Reply 9
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upthegunners
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Original post by ghostwalker
Since you're dealing with multiplication and division, it doesn't matter which order you do it in.

what order doesn't matter? sorry I dont understand
Original post by upthegunners
what order doesn't matter? sorry I dont understand


You can multiply by 2 and then factorise (which is essentially division),

Or you can factorise and then multiply by 2.

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