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    • Thread Starter

    nerves have kicked in for M1

    Need help with this:

    A particle P is moving so that its velocity, v ms^{-1}, after t seconds is given by v=3t^2 - 4t

    Initially P is at rest and is a displacment of 3m from a fixed point O.

    Find v when t=1.. okay so v=-1.

    ii) Find an expression for the displacment of P at any time t.
    d= \int (3t^2 - 4t)dt
    d=t^3 - 2t^2 +3

    Now this is where I need help!

    Find the distance travelled by the particle before it returns to its intial position. thanks

    EDIT" Is the "initial postion" when displacment =0?"
    • Thread Starter

    pleaseeeed some one help

    The formula you got through integration is correct, however note that it is for displacement from O (not distance traveled). You must consider the motion of the particle, when it changes direction, and find the displacement at those times, then draw out its path and add the separate distances to obtain the total distance traveled.

    Which paper is this? Thank you.

    Also, realize that there must be two times when the displacement of the particle from O is 0. Think about factorizing your derived equation for displacement.
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