You are Here: Home >< Maths

# Math Help :( Watch

1. Hey Guys

I need help with two math questions.

1.3sinx+1=4.8 , 0<x<2π

2. f(x)= x+1 0≤ x<2
4x-10 2≤x≤5
15-3x 5<x≤6
plot a graph of this function, stating its domain and range
evaluate f(0), f(4) and f(6)

Thank you so much for the help I would really appreciate it.
2. (Original post by YogieBear1001)
Hey Guys

I need help with two math questions.

1.3sinx+1=4.8 , 0<x<2π

2. f(x)= x+1 0≤ x<2
4x-10 2≤x≤5
15-3x 5<x≤6
plot a graph of this function, stating its domain and range
evaluate f(0), f(4) and f(6)

Thank you so much for the help I would really appreciate it.

No problem

What help do you need
3. (Original post by TenOfThem)
No problem

What help do you need
Thank you so much

Q1 is 3sinx+1=4.8 , 0<x<2π
4. (Original post by YogieBear1001)
Thank you so much

Q1 is 3sinx+1=4.8 , 0<x<2π
Yes, I saw

What help do you need

How far have you got
5. (Original post by TenOfThem)
Yes, I saw

What help do you need

How far have you got
3sinx+1=4.8 , 0<x<2π

I think im calculating it all wrong, but this bit --->+1=4.8 , 0<x<2π is confusing me.
6. (Original post by YogieBear1001)
3sinx+1=4.8 , 0<x<2π

I think im calculating it all wrong, but this bit --->+1=4.8 , 0<x<2π is confusing me.
subtract 1

So you have 3Sinx=3.8
7. (Original post by YogieBear1001)
3sinx+1=4.8 , 0<x<2π

I think im calculating it all wrong, but this bit --->+1=4.8 , 0<x<2π is confusing me.
I see TenOfThem's offline, so I'll try and help.
Is this the correct question? As I'm fairly sure the only solutions are complex. . .
8. (Original post by joostan)
I see TenOfThem's offline, so I'll try and help.
Is this the correct question? As I'm fairly sure the only solutions are complex. . .
Thank you
yes it is
9. (Original post by YogieBear1001)
Thank you
yes it is
Do you know about sinh(x) and complex numbers?
10. The angles are in radians; 2pi = 360 deg

3sinx+1=4.8
3sinx=3.8
sinx=3.8/3
sin-1(3.8/3) =

The rest is to you.
11. (Original post by m-s-96)
The angles are in radians; 2pi = 360 deg

3sinx+1=4.8
3sinx=3.8
sinx=3.8/3
sin-1(3.8/3) =

The rest is to you.
Oh Yes! Thank you so much
12. (Original post by YogieBear1001)
Oh Yes! Thank you so much
No problem.
13. (Original post by YogieBear1001)
Hey Guys

I need help with two math questions.

1.3sinx+1=4.8 , 0<x<2π
You're going to have a problem with that!

As x varies between 0 and 2pi, sinx takes on values from -1 to +1 so the max value of 3sin x is 3 and the max value of 3sin x + 1 is 4 - you can never reach 4.8 with real values of x!
14. (Original post by davros)
You're going to have a problem with that!

As x varies between 0 and 2pi, sinx takes on values from -1 to +1 so the max value of 3sin x is 3 and the max value of 3sin x + 1 is 4 - you can never reach 4.8 with real values of x!
Thank you!
15. (Original post by davros)
You're going to have a problem with that!

As x varies between 0 and 2pi, sinx takes on values from -1 to +1 so the max value of 3sin x is 3 and the max value of 3sin x + 1 is 4 - you can never reach 4.8 with real values of x!
The value for 'x' stated in the question represents the angle, not the value after applying sin.

Yes you are correct, sin only takes -1 to +1 and therefore 3sin + 1 is -4 to 4

:P

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: May 13, 2013
Today on TSR

### Am I pregnant?

...or just paranoid?

### A robot wrote Harry Potter?

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.