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# Logarithms Watch

1. I really struggle on logarithms

2logaN-loga(3N-4)=loga2

2. (Original post by strawbericalpony)
I really struggle on logarithms

2logaN-loga(3N-4)=loga2

Can you use your log rules to help you rewrite the 1st term on the left, and then combine it with the second term?
3. (Original post by davros)
Can you use your log rules to help you rewrite the 1st term on the left, and then combine it with the second term?
Yeah I've got as far as

logaN^2 - loga(3N-4) = loga2

logaN^2/3n-4 = loga2

and then I'm confused
4. (Original post by strawbericalpony)
Yeah I've got as far as

logaN^2 - loga(3N-4) = loga2

logaN^2/3n-4 = loga2

and then I'm confused
OK, that's great so now you have:

log (something) = log(something else)

so you must have

something = something else

i.e. you can remove the logarithms (technically you're raising a to the power of both sides), and that gives you an equation involving N which you can rearrange to get a quadratic
5. After removing logarithms, (cancelling by ) on both sides.

It becomes an effortless quadratic which can be solved any way you please.

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