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1. a curve y=f(x) is given implicitly by the equation
y3 +x3y+tanxy2-x4=4

Thanks for the help
2. (Original post by achu2k11)
a curve y=f(x) is given implicitly by the equation
y3 +x3y+tanxy2-x4=4

Thanks for the help
Do you know how to differentiate implicitly?
3. Differentiate each term with respect to x.

For example .

Once you've done that, solve for dy/dx.

Find the value of y when x=0. Put those x and y values in your expression for dy/dx.

4. (Original post by joostan)
Do you know how to differentiate implicitly?
Yeah, Can you check if this is right

dy/dx (3x2+y2sec2(x)-4x3)=3y2+2ytan(x)
5. (Original post by achu2k11)
Yeah, Can you check if this is right

dy/dx (3x2+y2sec2(x)-4x3)=3y2+2ytan(x)
I disagree with this. . .
You also need to use the product rule
6. (Original post by achu2k11)
Yeah, Can you check if this is right

dy/dx (3x2+y2sec2(x)-4x3)=3y2+2ytan(x)
You are sort of getting there but how are you differentiating exactly?

how did you differentiate x3y and and tan(x)y2?
7. (Original post by hoodboilu4)
You are sort of getting there but how are you differentiating exactly?

how did you differentiate x3y and and tan(x)y2?
Isn't using product rule of differentiation
8. (Original post by achu2k11)
Isn't using product rule of differentiation
Yes so what were you get when you differentiated those two?
9. (Original post by hoodboilu4)
Yes so what were you get when you differentiated those two?
Is it:

3x2dy/dx y+x3

and

y2sec(x)dy/dx+2ytan(x)
10. (Original post by achu2k11)
Is it:

3x2dy/dx y+x3

and

y2sec(x)dy/dx+2ytan(x)
You seem to be getting confused with your s
11. (Original post by achu2k11)
Is it:

3x2dy/dx y+x3

and

y2sec(x)dy/dx+2ytan(x)
It's supposed to be 3x2y + x3 dy/dx

and y2sec(x) + 2ytan(x)dy/dx
12. (Original post by hoodboilu4)
It's supposed to be 3x2y + x3 dy/dx

and y2sec(x) + 2ytan(x)dy/dx
You mean
You're missing a squared
13. (Original post by joostan)
You mean
You're missing a squared
I am indeed :P

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