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# Chain Rule watch

1. Hey i'm a bit stumped with this question? Do I have to re-arrange to get dt/ds amd dr/ds on their own?

Thanks
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2. (Original post by mathslover786)
Hey i'm a bit stumped with this question? Do I have to re-arrange to get dt/ds amd dr/ds on their own?

Thanks
That would be the way I'd do it, though I look to get ds/dt, rather than dt/ds.
3. (Original post by ghostwalker)
That would be the way I'd do it, though I look to get ds/dt, rather than dt/ds.
I got dt/ds to be r/(c·(r - 2·m)) so would ds/dt be the reciprocol?
4. (Original post by mathslover786)
I got dt/ds to be r/(c·(r - 2·m)) so would ds/dt be the reciprocol?
Even the reciprocal, yes.

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