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    Do you guys know how to solve question 3.29(b)? It's from Hodder Practice in Physics, the answer given is 830W. Thank you very much
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    OK, so:

    Power = Work Done / Time taken

    Hopefully you found out Work Done from earlier part....

    Now, speed = distance * time ==> time = speed / distance...
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    Ah, I get it, thank you very much yea :-)
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    (Original post by Piguy)
    OK, so:

    ***
    ***

    = 828 W = 830 W (2sf)
    We appreciate your wanting to help, but please note the guidelines for replying to questions

    http://www.thestudentroom.co.uk/wiki...ring_questions

    It asks that you do not post complete solutions to calculations.
    The idea is to help the poster answer it for himself, and not to do the question for him.

    Thanks for your cooperation in this.
 
 
 
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