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# Core 2 help Watch

1. ( I'm going to use a # for theta)

Solve the equation:
tan#= 2sin# for 0<(or equal to) # <(or equal to) 360

could it be explained as I never really got this, thanks.
2. (Original post by Rdgreen)
( I'm going to use a # for theta)

Solve the equation:
tan#= 2sin# for 0<(or equal to) # <(or equal to) 360

could it be explained as I never really got this, thanks.
tan# = (sin#)/(Cos#)

so rearrange the question and we have tan#-2sin#=0
This implies [(sin#/cos#)-2sin#]=0 factor out the sin# implies
sin#[(1/cos#)-2]=0 (note, you're not allowed to divide by sin# as sin# may equal 0 and you're just not allowed to divide by zero in mathematics!)
hence, sin#=0 which gives #=0,180,360
AND [(1/cos#)-2]=0 which gives (eventually, by multiplying by cos#) cos# = 1/2. Hence # = 60 or (360-60)=300
3. (Original post by hecandothatfromran)
tan# = (sin#)/(Cos#)

so rearrange the question and we have tan#-2sin#=0
This implies [(sin#/cos#)-2sin#]=0 factor out the sin# implies
sin#[(1/cos#)-2]=0 (note, you're not allowed to divide by sin# as sin# may equal 0 and you're just not allowed to divide by zero in mathematics!)
hence, sin#=0 which gives #=0,180,360
AND [(1/cos#)-2]=0 which gives (eventually, by multiplying by cos#) cos# = 1/2. Hence # = 45 or (360-45)=315
cos#=1/2 -> #=60 or 300
4. (Original post by ztibor)
cos#=1/2 -> #=60 or 300
Thanks! I fixed it now!
5. (Original post by hecandothatfromran)
Thanks! I fixed it now!
np

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