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# Logs equation watch

1. the curve y=5^(x-1) intersects y=2^x

ive logged both of the sides to get

(x-1)log5=xlog2

but i dont know how id get x on one side, unless i take away xlog2???
2. (Original post by VeeOMGlob)
the curve y=5^(x-1) intersects y=2^x

ive logged both of the sides to get

(x-1)log5=xlog2

but i dont know how id get x on one side, unless i take away xlog2???
Expand the brackets, rearrange then factor out the x
3. (Original post by VeeOMGlob)
the curve y=5^(x-1) intersects y=2^x

ive logged both of the sides to get

(x-1)log5=xlog2

but i dont know how id get x on one side, unless i take away xlog2???
Expand the LHS of the equation.
4. as in
0=(x-1)log5-xlog2
to
0=xlog5-log5-xlog2
to
log5=xlog5/2
to
log5/log5/2=x
so x=1.76

can i do that?
sorry for being pedantic, logarithms are my weakness :/

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