A person is throwing a shotput at an alngle, theta, to the horizontal. Given that the accelleration, a, is constant, deduce that the force, F exerted on the shot by the person is
So far I have that F has a vertical and horizontal component.
= vertical component, is the horizontal component.
Vertical component has the force going up and gravity.
Horizontal component is just
Is there more rearranging to be done? Or have I gone wrong with the forces?
Dynamics - shotput question help Watch
- Thread Starter
- 16-05-2013 15:02
- Study Helper
- 16-05-2013 18:41
F is the force. Do you want to treat it as a scalar or a vector? I'd go for a scalar myself. Things like then make sense (but aren't required), however you can't then use to find F.
When using F=ma, the F in this equation is the resultant force. So vertically you'd have
Because the acceleration is at an angle theta to the horizontal, means the resultant force is at an angle theta to the horizontal, not F is at an angle theta to the horizontal.Last edited by ghostwalker; 16-05-2013 at 18:43.