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# C2 - Question watch

1. How do you do the last part?

In the mark scheme it says something about perpendicular distance, can someone explain this to me?
2. (Original post by IShouldBeRevising_)
How do you do the last part?

In the mark scheme it says something about perpendicular distance, can someone explain this to me?
Shortest distance from a point to a line is the perpendicular distance. So drop a perpendicular from T to the line AC. What's its length?
3. (Original post by ghostwalker)
Shortest distance from a point to a line is the perpendicular distance. So drop a perpendicular from T to the line AC. What's its length?
Thanks, how do you work out the length of the line, it says in the mark scheme 914 * sin 70??
4. well 914 should be the answer to part a then because its perpendicular its right angle trig.
5. AC is 150m so the perpendicular is half the way along that line
6. (Original post by Goods)
well 914 should be the answer to part a then because its perpendicular its right angle trig.

(Original post by PKMN TRN JAM)
AC is 150m so the perpendicular is half the way along that line
I don't understand how you work out the distance of the perpendicular line?
7. (Original post by IShouldBeRevising_)
I don't understand how you work out the distance of the perpendicular line?
You've got A-T
you've got angle A
You've got A- perpendicular

I think you can use the sin rule from there
8. (Original post by IShouldBeRevising_)
Thanks, how do you work out the length of the line, it says in the mark scheme 914 * sin 70??
Don't forget the perpendicular lines meets AC at 90 degrees, a right angle.

Hence as others have said.
9. (Original post by IShouldBeRevising_)
I don't understand how you work out the distance of the perpendicular line?
Spoiler:
Show
10. (Original post by IShouldBeRevising_)

How do you do the last part?

In the mark scheme it says something about perpendicular distance, can someone explain this to me?
Here you go, this should help:
Attached Images

11. (Original post by GeorgeL3)
Here you go, this should help:

(Original post by Goods)
Spoiler:
Show

(Original post by ghostwalker)
Don't forget the perpendicular lines meets AC at 90 degrees, a right angle.

Hence as others have said.

(Original post by PKMN TRN JAM)
You've got A-T
you've got angle A
You've got A- perpendicular

I think you can use the sin rule from there
ok thank you guys... also just one more thing

For example if I have an arithmetic progression a = 7 d = 4

What does the following notation mean A sigma sign on top there is a 50 at the bottom there is n = 36 ? and on the side Un...

If at the bottom it was n=1 this would mean the sum of the first 50terms but I dont get what it means when n=36?
12. the sum of the 36th term and all the intermediate terms to the 50th term of the series U
13. (Original post by IShouldBeRevising_)
ok thank you guys... also just one more thing

For example if I have an arithmetic progression a = 7 d = 4

What does the following notation mean A sigma sign on top there is a 50 at the bottom there is n = 36 ? and on the side Un...

If at the bottom it was n=1 this would mean the sum of the first 50terms but I dont get what it means when n=36?
http://www.mathsisfun.com/algebra/sigma-notation.html

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