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    How do you do the last part?

    In the mark scheme it says something about perpendicular distance, can someone explain this to me?
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    (Original post by IShouldBeRevising_)
    How do you do the last part?

    In the mark scheme it says something about perpendicular distance, can someone explain this to me?
    Shortest distance from a point to a line is the perpendicular distance. So drop a perpendicular from T to the line AC. What's its length?
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    (Original post by ghostwalker)
    Shortest distance from a point to a line is the perpendicular distance. So drop a perpendicular from T to the line AC. What's its length?
    Thanks, how do you work out the length of the line, it says in the mark scheme 914 * sin 70??
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    well 914 should be the answer to part a then because its perpendicular its right angle trig.
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    AC is 150m so the perpendicular is half the way along that line
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    (Original post by Goods)
    well 914 should be the answer to part a then because its perpendicular its right angle trig.

    (Original post by PKMN TRN JAM)
    AC is 150m so the perpendicular is half the way along that line
    I don't understand how you work out the distance of the perpendicular line?
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    (Original post by IShouldBeRevising_)
    I don't understand how you work out the distance of the perpendicular line?
    You've got A-T
    you've got angle A
    You've got A- perpendicular

    I think you can use the sin rule from there
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    (Original post by IShouldBeRevising_)
    Thanks, how do you work out the length of the line, it says in the mark scheme 914 * sin 70??
    Don't forget the perpendicular lines meets AC at 90 degrees, a right angle.

    Hence as others have said.
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    (Original post by IShouldBeRevising_)
    I don't understand how you work out the distance of the perpendicular line?
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    (Original post by IShouldBeRevising_)


    How do you do the last part?

    In the mark scheme it says something about perpendicular distance, can someone explain this to me?
    Here you go, this should help:
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    (Original post by GeorgeL3)
    Here you go, this should help:

    (Original post by Goods)
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    (Original post by ghostwalker)
    Don't forget the perpendicular lines meets AC at 90 degrees, a right angle.

    Hence as others have said.

    (Original post by PKMN TRN JAM)
    You've got A-T
    you've got angle A
    You've got A- perpendicular

    I think you can use the sin rule from there
    ok thank you guys... also just one more thing

    For example if I have an arithmetic progression a = 7 d = 4

    What does the following notation mean A sigma sign on top there is a 50 at the bottom there is n = 36 ? and on the side Un...

    If at the bottom it was n=1 this would mean the sum of the first 50terms but I dont get what it means when n=36?
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    the sum of the 36th term and all the intermediate terms to the 50th term of the series U
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    (Original post by IShouldBeRevising_)
    ok thank you guys... also just one more thing

    For example if I have an arithmetic progression a = 7 d = 4

    What does the following notation mean A sigma sign on top there is a 50 at the bottom there is n = 36 ? and on the side Un...

    If at the bottom it was n=1 this would mean the sum of the first 50terms but I dont get what it means when n=36?
    http://www.mathsisfun.com/algebra/sigma-notation.html
 
 
 
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