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    http://filestore.aqa.org.uk/subjects...W-QP-JAN11.PDF Paper

    http://filestore.aqa.org.uk/subjects...W-MS-JAN11.PDF MS

    Question 1(b) why does point P have to be on the real axis at (8,0)? Why can't it be a anywhere on the circle? As you could draw a horizontal half line at any point on its circumference.

    Question 6(a) No matter how hard I try I cannot achieve the printed result. I differentiate it to (sect tant + sec^2t)/(sect + tant) -cost
    I have tried manipulating it but I can't achieve the printed result. Any hints?
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    (Original post by thers)
    http://filestore.aqa.org.uk/subjects...W-QP-JAN11.PDF Paper

    http://filestore.aqa.org.uk/subjects...W-MS-JAN11.PDF MS

    Question 1(b) why does point P have to be on the real axis at (8,0)? Why can't it be a anywhere on the circle? As you could draw a horizontal half line at any point on its circumference.

    Question 6(a) No matter how hard I try I cannot achieve the printed result. I differentiate it to (sect tant + sec^2t)/(sect + tant) -cost
    I have tried manipulating it but I can't achieve the printed result. Any hints?
    For 6)a) simplify the fraction.
    Spoiler:
    Show
    you'll get sec(t) - it's plain sailing from there using 1- cos^2t
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    (Original post by joostan)
    For 6)a) simplify the fraction.
    Spoiler:
    Show
    you'll get sec(t) - it's plain sailing from there using 1- cos^2t
    Thats the problem I'm having I can't simplify the fraction. I get it down to (tant +sect)/(1+sint) but can't make further progress.
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    (Original post by thers)
    Question 1(b) why does point P have to be on the real axis at (8,0)? Why can't it be a anywhere on the circle? As you could draw a horizontal half line at any point on its circumference.
    You were given \arg z_1 = 0, so you need the point on the circle where this condition is satisfied.
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    (Original post by justinawe)
    You were given \arg z_1 = 0, so you need the point on the circle where this condition is satisfied.
    Why can't I draw a half line that is horizontal (so argument is 0) at say point (4,2) which lies on the circle?
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    okay not sure if this is right.

    tant + sect/tant -cost

    tant/tant + cost - cost

    1/cost - cost

    1-cos^2t/cost

    sin^2t/cost

    sinttant
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    (Original post by thers)
    Why can't I draw a half line that is horizontal (so argument is 0) at say point (4,2) which lies on the circle?
    Not all horizontal lines have an argument of 0, where did you get that from?

    Argument is only 0 on the real axis. Draw a line from the origin to the point (4,2). You can clearly see the argument isn't 0.
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    (Original post by justinawe)
    Not all horizontal lines have an argument of 0, where did you get that from?

    Argument is only 0 on the real axis. Draw a line from the origin to the point (4,2). You can clearly see the argument isn't 0.
    Oh right, I've become incredibly rusty on loci lol. If that's the case then why can't I put P on the origin?
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    (Original post by thers)
    Oh right, I've become incredibly rusty on loci lol. If that's the case then why can't I put P on the origin?
    \arg (0) is indeterminate, because you can't exactly draw a line from the origin to the origin, as such.
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    (Original post by justinawe)
    \arg (0) is indeterminate, because you can't exactly draw a line from the origin to the origin, as such.
    Right okay thanks for the help.
 
 
 
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