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    ok im stuck on the last part of this question
    (ref: Heineman P1, pg 98, q46):
    m => 2x + 3y = 15
    the point P lies on m and has x co-ordinate = -3
    therefore P(-3,7).
    the points A(1,0) and B(5,6) lie on the line => y = (3/2)x - 3/2.
    [q] show that PA = PB.

    thanks in advance: adam.
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    √(3²+6²) = √45 = PA
    √(8²+1²) = √65 = PB

    I think the question is wrong. They obviously have different directions and by pythagoras it's clear they have different lengths.
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    ok, what are you doing there to find PA and PB i dont understand :x

    edit: nm.
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    P(-3,7)
    A(1,0)
    B(5,6)

    using,
    len=sqrt((x1-x2)^2 + (y1-y2)^2)

    PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
    PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

    hence PA=PB
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    (Original post by Fermat)
    P(-3,7)
    A(1,0)
    B(5,6)

    using,
    len=sqrt((x1-x2)^2 + (y1-y2)^2)

    PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
    PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

    hence PA=PB
    behold fermat, mathematical genius.

    hows the theorem going?
 
 
 

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