You are Here: Home

pure1 simple question.. watch

1. ok im stuck on the last part of this question
(ref: Heineman P1, pg 98, q46):
m => 2x + 3y = 15
the point P lies on m and has x co-ordinate = -3
therefore P(-3,7).
the points A(1,0) and B(5,6) lie on the line => y = (3/2)x - 3/2.
[q] show that PA = PB.

2. √(3²+6²) = √45 = PA
√(8²+1²) = √65 = PB

I think the question is wrong. They obviously have different directions and by pythagoras it's clear they have different lengths.
3. ok, what are you doing there to find PA and PB i dont understand :x

edit: nm.
4. P(-3,7)
A(1,0)
B(5,6)

using,
len=sqrt((x1-x2)^2 + (y1-y2)^2)

PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

hence PA=PB
5. (Original post by Fermat)
P(-3,7)
A(1,0)
B(5,6)

using,
len=sqrt((x1-x2)^2 + (y1-y2)^2)

PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

hence PA=PB
behold fermat, mathematical genius.

hows the theorem going?

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 20, 2004
Today on TSR

University open days

• University of East Anglia (UEA)
Could you inspire the next generation? Find out more about becoming a Secondary teacher with UEA… Postgraduate
Thu, 18 Oct '18
• University of Warwick
Sat, 20 Oct '18
• University of Sheffield