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# pure1 simple question.. watch

1. ok im stuck on the last part of this question
(ref: Heineman P1, pg 98, q46):
m => 2x + 3y = 15
the point P lies on m and has x co-ordinate = -3
therefore P(-3,7).
the points A(1,0) and B(5,6) lie on the line => y = (3/2)x - 3/2.
[q] show that PA = PB.

2. √(3²+6²) = √45 = PA
√(8²+1²) = √65 = PB

I think the question is wrong. They obviously have different directions and by pythagoras it's clear they have different lengths.
3. ok, what are you doing there to find PA and PB i dont understand :x

edit: nm.
4. P(-3,7)
A(1,0)
B(5,6)

using,
len=sqrt((x1-x2)^2 + (y1-y2)^2)

PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

hence PA=PB
5. (Original post by Fermat)
P(-3,7)
A(1,0)
B(5,6)

using,
len=sqrt((x1-x2)^2 + (y1-y2)^2)

PA=sqrt((-3-1)^2 + (7-0)^2)=sqrt(16+49)=sqrt(65)
PB=sqrt((-3-5)^2 + (7-6)^2)=sqrt(64+1)=sqrt(65)

hence PA=PB
behold fermat, mathematical genius.

hows the theorem going?

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