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OCR (Not MEI) C2 May 2013 (17.5.13) UO Markscheme Watch

1. How did you find it?
2. 1. 6.39 [4]
2i) 106, 254 [3]
2ii) 71.6, 252 [3]
3i) 64+960x+6000x^2 [4]
3ii) c=-11 [3]
4a) (5/4)x^4-3x^2+x+c [3]
4bi) -12x^-2+c [2]
4bii) a=+2 [3]
5i) 62.2 [4]
5ii) 34 [4]
6i) 963 [3]
6ii) 17 [6]
7i) show that [4]
7ii) 37/30 [5]
8ia) (0,1) [1]
8ib) (0,4) [1]
8ic) a>1 0<b<1 [2]
8ii) show that [5]
9i) 15 [2]
9ii) (2x+1)(2x-3)(x+1) [6]
9iii) 2/3pi, pi, 4/3pi [4]

3. 1. 6.39
2i) 106, 254
2ii) 71.6, 252
3i) 64+960x+6000x^2
3ii) c=-11
4i) (5/4)x^4-3x^2+x+c
4ii) -12x^-2+c
4iii) a=+2
5i) 62.2
5ii) 34
6i) 58.2
6ii) 17
7i) show that
7ii) 37/30
8ia) (0,1)
8ib) (0,4)
8ic) a>=1 0<b<1
8ii) show that
9i) 15
9ii) (2x+1)(2x-3)(x+1)
9iii) 2/3pi, pi, 4/3pi
For 4 ii they asked for a positive constant. So you should put only 2 in fact.
First term was 6. 2nd 7.8, so common difference was 1.8. S30=30/2(2*6+29*1.8)=963
For 8ic, I think they asked for specific possible coordinates, not the set. I said a=2, b=1.
4. (Original post by purplemind)
For 4 ii they asked for a positive constant. So you should put only 2 in fact.
First term was 6. 2nd 7.8, so common difference was 1.8. S30=30/2(2*6+29*1.8)=963
For 8ic, I think they asked for specific possible coordinates, not the set. I said a=2, b=1.
Yea, I put "+2" to emphasise that it was only the positive
Correct, it wanted total, so 963. Got the right in exam but wrong doing working now. Corrected, thank you.
Yea, I wrote that to show what you could have. Think b would have to be smaller than one, as 4(1^x) is always 4, thus straight line?

5. Yea, I put "+2" to emphasise that it was only the positive
Correct, it wanted total, so 963. Got the right in exam but wrong doing working now. Corrected, thank you.
Yea, I wrote that to show what you could have. Think b would have to be smaller than one, as 4(1^x) is always 4, thus straight line?
Well, that is true. I only thought about the place they can cross.
6. Can you put the marks for the question by the question please?
7. For 1. I got 9.58 or something...got 6.39 and then x by 3/2
8. I think I got most of it right which is good as I mucked up c1 on Monday. Does anyone remember how to do the show that logs question, 8ii? As I don't think I got it right
9. Relatively easy a couple of silly mistakes, and I think I got the answer wrong for one of them... but oh well :P How did you find it? Can someone post the markscheme on here?
10. Would anyone mind putting the actual Qs up if you have them to hand?
Thought the exam went really well and then came out and realised that I had made ridiculous number of mistakes
Hopefully stats will go well and think I got around 62 in C1 so with a resit next year in this hopefully I will be ok :-)
11. Does anyone have the question paper?

12. 1. 6.39
2i) 106, 254
2ii) 71.6, 252
3i) 64+960x+6000x^2
3ii) c=-11
4i) (5/4)x^4-3x^2+x+c
4ii) -12x^-2+c
4iii) a=+2
5i) 62.2
5ii) 34
6i) 963
6ii) 17
7i) show that
7ii) 37/30
8ia) (0,1)
8ib) (0,4)
8ic) a>1 0<b<1
8ii) show that
9i) 15
9ii) (2x+1)(2x-3)(x+1)
9iii) 2/3pi, pi, 4/3pi
Me and my friend both got 36 for 5ii) are you sure you're not wrong?
13. Hi, what was question 5?? (:

14. 1. 6.39
2i) 106, 254
2ii) 71.6, 252
3i) 64+960x+6000x^2
3ii) c=-11
4i) (5/4)x^4-3x^2+x+c
4ii) -12x^-2+c
4iii) a=+21
5i) 62.2
5ii) 34
6i) 963
6ii) 17
7i) show that
7ii) 37/30
8ia) (0,1)
8ib) (0,4)
8ic) a>1 0<b<1
8ii) show that
9i) 15
9ii) (2x+1)(2x-3)(x+1)
9iii) 2/3pi, pi, 4/3pi
Are these 100% right?

For 3)i I got 64+960x +3000x^2 rather 6000x ^2

For 4)ii I got 1/2
I think I got everything else right. Though I can't remember my answers for q 5/6
15. Anyone hazard a guess at the grade boundaries? (it was relatively easy)
16. (Original post by Ellie_Rosa)
I think I got most of it right which is good as I mucked up c1 on Monday. Does anyone remember how to do the show that logs question, 8ii? As I don't think I got it right
8 'show that' question:
y=y
a^x=4b^x
log2(a^x)=log2(4)+log2(b^x)
x(log2(a)-log2(b)=2
ab=2 therefore b=2/a, sub this in to get
x(log2(a)-log2(2/a))=2
x(log2(a)-(log2(2)-log2(a))=2
x(log2(a)-1+log2(a))=2
x(2log2(a)-a)=2
Therefore x= 2/(2log2(a)-1)
Hope this helps! (:
17. hoq did you find the paper in comparison to others
18. it was okay I guess....
19. (Original post by scrona)
hoq did you find the paper in comparison to others
Much better than C1 but so many silly mistakes which are worrying me now ( I did 8 C2 pastpapers before this and I think it was one of the easier ones if not the easiest..
20. (Original post by scrona)
hoq did you find the paper in comparison to others
Didn't think it was too bad imo. Does anyone remember question 4iii?

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