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    1. 6.39 [4]
    2i) 106, 254 [3]
    2ii) 71.6, 252 [3]
    3i) 64+960x+6000x^2 [4]
    3ii) c=-11 [3]
    4a) (5/4)x^4-3x^2+x+c [3]
    4bi) -12x^-2+c [2]
    4bii) a=+2 [3]
    5i) 62.2 [4]
    5ii) 34 [4]
    6i) 963 [3]
    6ii) 17 [6]
    7i) show that [4]
    7ii) 37/30 [5]
    8ia) (0,1) [1]
    8ib) (0,4) [1]
    8ic) a>1 0<b<1 [2]
    8ii) show that [5]
    9i) 15 [2]
    9ii) (2x+1)(2x-3)(x+1) [6]
    9iii) 2/3pi, pi, 4/3pi [4]

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    (Original post by [email protected])
    1. 6.39
    2i) 106, 254
    2ii) 71.6, 252
    3i) 64+960x+6000x^2
    3ii) c=-11
    4i) (5/4)x^4-3x^2+x+c
    4ii) -12x^-2+c
    4iii) a=+2
    5i) 62.2
    5ii) 34
    6i) 58.2
    6ii) 17
    7i) show that
    7ii) 37/30
    8ia) (0,1)
    8ib) (0,4)
    8ic) a>=1 0<b<1
    8ii) show that
    9i) 15
    9ii) (2x+1)(2x-3)(x+1)
    9iii) 2/3pi, pi, 4/3pi
    For 4 ii they asked for a positive constant. So you should put only 2 in fact.
    Are you sure about 6i?
    First term was 6. 2nd 7.8, so common difference was 1.8. S30=30/2(2*6+29*1.8)=963
    For 8ic, I think they asked for specific possible coordinates, not the set. I said a=2, b=1.
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    (Original post by purplemind)
    For 4 ii they asked for a positive constant. So you should put only 2 in fact.
    Are you sure about 6i?
    First term was 6. 2nd 7.8, so common difference was 1.8. S30=30/2(2*6+29*1.8)=963
    For 8ic, I think they asked for specific possible coordinates, not the set. I said a=2, b=1.
    Yea, I put "+2" to emphasise that it was only the positive
    Correct, it wanted total, so 963. Got the right in exam but wrong doing working now. Corrected, thank you.
    Yea, I wrote that to show what you could have. Think b would have to be smaller than one, as 4(1^x) is always 4, thus straight line?
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    (Original post by [email protected])
    Yea, I put "+2" to emphasise that it was only the positive
    Correct, it wanted total, so 963. Got the right in exam but wrong doing working now. Corrected, thank you.
    Yea, I wrote that to show what you could have. Think b would have to be smaller than one, as 4(1^x) is always 4, thus straight line?
    Well, that is true. I only thought about the place they can cross.
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    Can you put the marks for the question by the question please?
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    For 1. I got 9.58 or something...got 6.39 and then x by 3/2
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    I think I got most of it right which is good as I mucked up c1 on Monday. Does anyone remember how to do the show that logs question, 8ii? As I don't think I got it right
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    Relatively easy a couple of silly mistakes, and I think I got the answer wrong for one of them... but oh well :P How did you find it? Can someone post the markscheme on here?
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    Would anyone mind putting the actual Qs up if you have them to hand?
    Thought the exam went really well and then came out and realised that I had made ridiculous number of mistakes
    Hopefully stats will go well and think I got around 62 in C1 so with a resit next year in this hopefully I will be ok :-)
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    Does anyone have the question paper?
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    (Original post by [email protected])
    1. 6.39
    2i) 106, 254
    2ii) 71.6, 252
    3i) 64+960x+6000x^2
    3ii) c=-11
    4i) (5/4)x^4-3x^2+x+c
    4ii) -12x^-2+c
    4iii) a=+2
    5i) 62.2
    5ii) 34
    6i) 963
    6ii) 17
    7i) show that
    7ii) 37/30
    8ia) (0,1)
    8ib) (0,4)
    8ic) a>1 0<b<1
    8ii) show that
    9i) 15
    9ii) (2x+1)(2x-3)(x+1)
    9iii) 2/3pi, pi, 4/3pi
    Me and my friend both got 36 for 5ii) are you sure you're not wrong?
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    Hi, what was question 5?? (:
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    (Original post by [email protected])
    1. 6.39
    2i) 106, 254
    2ii) 71.6, 252
    3i) 64+960x+6000x^2
    3ii) c=-11
    4i) (5/4)x^4-3x^2+x+c
    4ii) -12x^-2+c
    4iii) a=+21
    5i) 62.2
    5ii) 34
    6i) 963
    6ii) 17
    7i) show that
    7ii) 37/30
    8ia) (0,1)
    8ib) (0,4)
    8ic) a>1 0<b<1
    8ii) show that
    9i) 15
    9ii) (2x+1)(2x-3)(x+1)
    9iii) 2/3pi, pi, 4/3pi
    Are these 100% right?

    For 3)i I got 64+960x +3000x^2 rather 6000x ^2

    For 4)ii I got 1/2
    I think I got everything else right. Though I can't remember my answers for q 5/6
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    Anyone hazard a guess at the grade boundaries? (it was relatively easy)
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    (Original post by Ellie_Rosa)
    I think I got most of it right which is good as I mucked up c1 on Monday. Does anyone remember how to do the show that logs question, 8ii? As I don't think I got it right
    8 'show that' question:
    y=y
    a^x=4b^x
    log2(a^x)=log2(4)+log2(b^x)
    x(log2(a)-log2(b)=2
    ab=2 therefore b=2/a, sub this in to get
    x(log2(a)-log2(2/a))=2
    x(log2(a)-(log2(2)-log2(a))=2
    x(log2(a)-1+log2(a))=2
    x(2log2(a)-a)=2
    Therefore x= 2/(2log2(a)-1)
    Hope this helps! (:
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    hoq did you find the paper in comparison to others
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    it was okay I guess....
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    (Original post by scrona)
    hoq did you find the paper in comparison to others
    Much better than C1 but so many silly mistakes which are worrying me now ( I did 8 C2 pastpapers before this and I think it was one of the easier ones if not the easiest..
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    (Original post by scrona)
    hoq did you find the paper in comparison to others
    Didn't think it was too bad imo. Does anyone remember question 4iii?
 
 
 
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