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Easy...? trig question for core 4 aqa

Could anyone help me with parts question 6 (c) (i) & (ii) please on this paper http://filestore.aqa.org.uk/subjects/AQA-MPC4-W-QP-JUN09.PDF please? Literally no clue how to do it, thanks for help :smile:
Reply 1
Original post by Joeyye
Could anyone help me with parts question 6 (c) (i) & (ii) please on this paper http://filestore.aqa.org.uk/subjects/AQA-MPC4-W-QP-JUN09.PDF please? Literally no clue how to do it, thanks for help :smile:


Draw a right angled triangle, label one angle as β\beta

Label the opposite and adjacent sides to give the required tanβ\tan \beta

Use Pythagoras to find the hypotenuse

Find cosβ\cos \beta and sinβ\sin \beta
Reply 2
Original post by TenOfThem
Draw a right angled triangle, label one angle as β\beta

Label the opposite and adjacent sides to give the required tanβ\tan \beta

Use Pythagoras to find the hypotenuse

Find cosβ\cos \beta and sinβ\sin \beta[/

how can i label two sides when it only says 2root2?
Reply 3
Original post by Joeyye


how can i label two sides when it only says 2root2?


Well there would be infinite ways but I would suggest using 222\sqrt{2} and 1 as the easiest version

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