D2O
If D2O is added to a sample and exchanges with the H in the OH and NH groups in the sample, why doesn't the HOD formed produce a splitting pattern?
I think it does produce a peak, but it's so far away from the values we use for H that it's not on our spectra?
Original post by Holz888
I think it does produce a peak, but it's so far away from the values we use for H that it's not on our spectra?
yeah maybe
Anyone else? I'm still a bit confused
You can get a signal from HOD which will be a singlet, but this is very common in NMR solvents and is easily identified/ignored. For example it turns up at 1.56 ppm in CDCl3 (one of the most common NMR solvents) 
A-level exams will not show impurities, residual solvent peaks etc. for clarity.
A-level exams will not show impurities, residual solvent peaks etc. for clarity.
Original post by EierVonSatan
You can get a signal from HOD which will be a singlet, but this is very common in NMR solvents and is easily identified/ignored. For example it turns up at 1.56 ppm in CDCl3 (one of the most common NMR solvents)
A-level exams will not show impurities, residual solvent peaks etc. for clarity.
A-level exams will not show impurities, residual solvent peaks etc. for clarity.
Oh in understand now, thanks
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