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Polar graphing

Question asks me to draw r = a(1 - cost), (t = theta).

I drew a table of values as completed the question but now when I look over my notes a dimple is only meant to occur when q p < 2q when r = a(p +qcost).

In our example p = 1, q = -1, 2q = -2 so p > 2q but there is still a dimple???
Reply 1
Original post by miketree
Question asks me to draw r = a(1 - cost), (t = theta).

I drew a table of values as completed the question but now when I look over my notes a dimple is only meant to occur when q p < 2q when r = a(p +qcost).

In our example p = 1, q = -1, 2q = -2 so p > 2q but there is still a dimple???


by dimple do you mean the bit inside

if so, you should not have one for this question
Reply 2
Original post by TenOfThem
by dimple do you mean the bit inside

if so, you should not have one for this question


Untitled.png

A dimple like the above, this is the general shape but it's not to scale.
Reply 3
Original post by miketree
Untitled.png

A dimple like the above, this is the general shape but it's not to scale.


Oh, yes you should have that

It is this bit that only appears with, for example 1+2Cosθ\theta

http://www.wolframalpha.com/input/?i=r%3D1%2B2cos%28theta%29
Reply 4
Original post by TenOfThem
...


Ok so from what I understand, p=pp = |p| and q=qq = |q|, i.e. 'dimple' when qp<2q|q| \leq |p| < |2q|.

Is that all ok or no?

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