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Edexcel C3 - 12.06.06 - The 'how did it go' thread!

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Lusus Naturae
Could have been worse but naturally my mind went blank on a couple of trivial parts, they were "show that...4k+sin4k+2=0" and . Should shoot myself for that :frown: Quite sure rest was correct though so around 90UMS I guess.
I still don't get that... :confused:
Reply 181
Avatar for Rabite
Rabite
8
Yeah. Exactly.

And can anyone remember the ln question?
was it f--> ln(x+k) and
g--> |2x -k|?
BovineBeast
I don't really think so. Negative Infinity isn't a real number.

Guess that makes sense, thanks
Think so.
Reply 184
Avatar for ellen8899
ellen8899
is anyone remember how many marks the Teperture lost in per minutes worth? thanks
Reply 185
Avatar for Rabite
Rabite
8
I'm still trying to work out why fg(k/4) is 0.5k...
I got 1.5k :x

The temp one was...4 marks I think. Maybe 3.
Reply 186
Avatar for Sollytear
Sollytear
BovineBeast
Er, that's 1.64.


Ok so -1.64 then :P MB but its def negitive...
Reply 187
Avatar for yo_dude
yo_dude
Malik
Definetly not 56, compared to the Jan06 and Jun05 I think larger majority would have found this paper easier. At best its just going to be the typical 60/75 80% boundary.


Do you really think this paper was easier than the past 2 years?

Besides, we have some foreigners amongst us.. who are probably taking the answers from us right now :rolleyes: UP GO THE UMS BOUNDARIES :tsr2: :tsr2: :tsr2: :tsr2: :tsr2: :tsr2: :tsr2: :tsr2:


sigh..
Reply 188
Avatar for Malik
Malik
12
Rabite
I'm still trying to work out why fg(k/4) is 0.5k...
I got 1.5k :x

The temp one was...4 marks I think. Maybe 3.


Its comes down to how you treated the modulus in the question. I not sure which way was right so I cant really comment.
Reply 189
Avatar for Sollytear
Sollytear
fg(k/4) IS ln(1.5k) why are people saying its not.
Reply 190
Avatar for spacko101
spacko101
i think it is ln(1.5).

well how many marks was that one then? cause they're gone for me now.
Reply 191
Avatar for Sollytear
Sollytear
Ill show you again:

f(x) = ln(x + k)
g(x) = |2x - k|

fg(x) = ln(|2x - k| + k)

Lets x = 0.25k
Ln(|-0.5k| + k) = ln(1.5k)
You'll still get method marks for the earler part of the question.
spacko101
so absolutely NO ONE remembers how many marks the Sin2A thing was?



5 mark question...
Reply 194
Avatar for Malik
Malik
12
Sollytear
Ill show you again:

f(x) = ln(x + k)
g(x) = |2x - k|

fg(x) = ln(|2x - k| + k)

Lets x = 0.25k
Ln(|-0.5k| + k) = ln(1.5k)


Yea thats how I did it.
Reply 195
Avatar for Dal
Dal
2
that was quite a challenging paper.. anyone else feel like they rushed through it? i think i finished it.. although i know i didnt get that Sin2A questsion right.. the proving stuff was quite difficult but i think it was managable is u let it sit for a while..
ellen8899
is anyone remember how many marks the Teperture lost in per minutes worth? thanks


3 or 2 i fink
There were two questions I didn't finish, which totalled 10 marks :frown: but I think I got method marks for what I did do :smile:

I'll just have to hope there won't be too many silly mistakes in there, as they can cost me dear.
Reply 198
Avatar for spacko101
spacko101
i got up to:

f(x) = ln(x + k)
g(x) = |2x - k|

fg(x) = ln(|2x - k| + k)

then i went dumb. and cancelled the k's. lol. :biggrin:
Reply 199
Avatar for abshirf2
abshirf2
1
ok paper!

does anyone remember how they showed k=0.277 after the iterative questions? i just left it out cos i cud not do it, simple as.:frown:

i hope the c4 paper is really eas, it neeeds to be so i can get an A!:biggrin:

and it is Ln(1.5k) definite.

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