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    can anyone post up the proof for the formulae as proved in the heninemann m1 book. i am trying to prove them but i can't do it nor do i have the book. thanks
    i think there were 3 or 4 formulae e.g. v= u + at; etc.... thanks :tsr2:
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    why do u need their proofs?
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    Do you need proofs as to why they work or will this do:

    d/dt(s) = d/dt(ut + ½at²)
    v = u + at

    then:
    d/dt(v) = d/dt(u + at)
    a = a

    That's proof enough!
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    (Original post by yazan_l)
    why do u need their proofs?
    sorry, very simple proof, only how to get to the formulae; not proving that they work.

    for example, i think you start with a = (v-u)/t and use other formulae to set up simultaneous eqn.s and then the other formulae can be derived.

    never mind, it's just something thats on my mind as i can't remeber. it's in the m1 book anyway i'll take a look when i get one, but it'll b helpful if someone could copy it out.
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    Oh ok, start with v = u + at which I'll call 1 and s = 0.5(u + v)t which I'll call 2

    sub for v into 2: s = 0.5(u + u +at)t => s = ut + 0.5at²

    If v = u + at it follows that t = (v - u)/a
    sub this into 2: s = 0.5 (u + v)(v - u) / a => s = v² - u² / 2a => v² = u² + 2as

    And finally if v = u + at it follows that u = v - at
    sub this into 2: s = 0.5(2v-at)t => s = vt - 0.5at²

    And there you have it, a full set of SUVAT equations (valid only for constant acceleration). Also note that each one of the equations omits a different variable, hence me eliminating them above!
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    Yeah... and to come up with v = u + at you can just draw a velocity/time graph, noting that acceleration is the gradient of the line. Same with s = ut + 1/2 at^2, except that distance is area under the graph.
 
 
 
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