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# C4 Integration watch

1. Find the integral of 1/[1+(x-1)^1/2] using substitution u^2 = x-1

I'm sure this should be really easy, but I get to

2u/1+u

which I'm unable to integrate

Edit: Rep available!
2. Partial fractions? But there's only one denominator, which doesn't factorise -how do I do that?

Feeling stupid(er) now
3. Fine, delete your post and make me look worse thanks for that
4. think by parts... make it 2u(1+u)-1
5. (Original post by Apagg)
Find the integral of 1/[1+(x-1)^1/2] using substitution u^2 = x-1

I'm sure this should be really easy, but I get to

2u/1+u

which I'm unable to integrate
2u/1+u = (2+2u-2)/1+u = 2 - 2/(1+u), and then integrate as usual.
6. (Original post by Axon)
2u/1+u = (2+2u-2)/1+u = 2 - 2/(1+u), and then integrate as usual.
nice... even better than by parts! hehe
7. You genius Axon! Thank you, rep coming your way

Hate those sort of questions
8. (Original post by Apagg)
You genius Axon! Thank you, rep coming your way

Hate those sort of questions
you are welcome anyway!
9. Sorry But the question wants substitution only, so I couldn't use your method. Plus, you made me look silly
10. (Original post by Apagg)
Sorry But the question wants substitution only, so I couldn't use your method. Plus, you made me look silly
well u can use any method u want... because u DID use the substitution! (when did i make u look silly?)
11. You made a post and then deleted it, so my response to the post made it seem I was going crazy

I'm working through the book step by step, so only using the methods that have cropped up up to that point, if that makes sense
12. (Original post by Apagg)
You made a post and then deleted it, so my response to the post made it seem I was going crazy

I'm working through the book step by step, so only using the methods that have cropped up up to that point, if that makes sense
haha.. well i deleted it because i didnt see that u already reached where i stopped! sorry anyway...
13. Not to worry

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