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Physics AS levels Multiple Choice Help!
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physicshelp1
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A lead pellet is shot vertically upwards into a clay block that is stationary at the moment of impact
but is able to rise freely after impact.
The pellet hits the block with an initial velocity of 200ms–1. It embeds itself in the block and does not emerge.
How high above its initial position will the block rise?
(Mass of pellet = 5.0g; mass of clay block = 95g.)
How do i calculate it? please help with all steps.
Correct answer is 5.1 m but i dont know how to get it.
but is able to rise freely after impact.
The pellet hits the block with an initial velocity of 200ms–1. It embeds itself in the block and does not emerge.
How high above its initial position will the block rise?
(Mass of pellet = 5.0g; mass of clay block = 95g.)
How do i calculate it? please help with all steps.
Correct answer is 5.1 m but i dont know how to get it.
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usycool1
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#2
(Original post by physicshelp1)
A lead pellet is shot vertically upwards into a clay block that is stationary at the moment of impact
but is able to rise freely after impact.
The pellet hits the block with an initial velocity of 200ms–1. It embeds itself in the block and does not emerge.
How high above its initial position will the block rise?
(Mass of pellet = 5.0g; mass of clay block = 95g.)
How do i calculate it? please help with all steps.
Correct answer is 5.1 m but i dont know how to get it.
A lead pellet is shot vertically upwards into a clay block that is stationary at the moment of impact
but is able to rise freely after impact.
The pellet hits the block with an initial velocity of 200ms–1. It embeds itself in the block and does not emerge.
How high above its initial position will the block rise?
(Mass of pellet = 5.0g; mass of clay block = 95g.)
How do i calculate it? please help with all steps.
Correct answer is 5.1 m but i dont know how to get it.
Then use SUVAT (you have the initial speed, final speed and acceleration...you need to find s, the displacement) to get your answer.
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eagleeye1990s
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eagleeye1990s
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#4
(Original post by usycool1)
First use the principle of conservation of momentum to find the final velocity of the block and the pellet.
Then use SUVAT (you have the initial speed, final speed and acceleration...you need to find s, the displacement) to get your answer.
First use the principle of conservation of momentum to find the final velocity of the block and the pellet.
Then use SUVAT (you have the initial speed, final speed and acceleration...you need to find s, the displacement) to get your answer.
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Saisubu99
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#5
Momentum before collision = mu + m(0) = (5/1000) x 200 = 1
Momentum after collision = (m+m) x v = 0.1 x v
Conservation of momentum 1 = 0.1vv = 10 ms-1
v^2 = u^2 + 2as
v = 10
a =g = 9.81
u = 0
s= ?
10^2 = 0 + 2x9.81xs
S = 10^2/ (2x9.81)
S = 5.09 = 5.1
Momentum after collision = (m+m) x v = 0.1 x v
Conservation of momentum 1 = 0.1vv = 10 ms-1
v^2 = u^2 + 2as
v = 10
a =g = 9.81
u = 0
s= ?
10^2 = 0 + 2x9.81xs
S = 10^2/ (2x9.81)
S = 5.09 = 5.1
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Manahil01
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mallikabomjan
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Eimmanuel
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#8
(Original post by Manahil01)
Why did you use 0.1 instead of the 0.095 kg
Why did you use 0.1 instead of the 0.095 kg
By the way, to Manahil01, a warm welcome to TSR.
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