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Rich
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#1
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#1
Hey there,

I have received a PM from bono asking for an interesting maths problem/puzzle... well here we go:

Prove that

sin(pi/(2n + 1)) * sin(2*pi/(2n + 1)) * ... * sin(n*pi/(2n + 1)) = sqrt(2n + 1)/(2^n)

I haven't done it myself yet, so I can't give any hints, lol.

Good luck!
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username9816
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(Original post by rahaydenuk)
Hey there,

I have received a PM from bono asking for an interesting maths problem/puzzle... well here we go:

Prove that

sin(pi/(2n + 1)) * sin(2*pi/(2n + 1)) * ... * sin(n*pi/(2n + 1)) = sqrt(2n + 1)/(2^n)

I haven't done it myself yet, so I can't give any hints, lol.

Good luck!
I'll let "theone" battle this one.
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Rich
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#3
(Original post by bono)
I'll let "theone" battle this one.
While you watch from the sidelines? Maths is not a spectator sport!
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username9816
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#4
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#4
(Original post by rahaydenuk)
While you watch from the sidelines? Maths is not a spectator sport!
Your problems are solid!!
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makesomenoise
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This won't by chance have anything to do with the Maclaurin approximation? Or am I way off track?
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makesomenoise
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#6
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#6
(Original post by rahaydenuk)
While you watch from the sidelines? Maths is not a spectator sport!
Well it is to our physicist brethren.
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Rich
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#7
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(Original post by XTinaA)
This won't by chance have anything to do with the Maclaurin approximation? Or am I way off track?
Perhaps, as I say I've not done it!
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makesomenoise
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#8
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#8
(Original post by rahaydenuk)
Perhaps, as I say I've not done it!
It hurts to look at, it hurts more that I can't do it. I'd love to see the answer though. I'd try but I wouldn't know where to start.
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Nylex
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#9
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#9
(Original post by XTinaA)
It hurts to look at, it hurts more that I can't do it. I'd love to see the answer though. I'd try but I wouldn't know where to start.
Same here, lol.
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username9816
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#10
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#10
(Original post by Nylex)
Same here, lol.
ooooo, what is that fancy sin thingy?!
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Nylex
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#11
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#11
(Original post by bono)
ooooo, what is that fancy sin thingy?!
?
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username9816
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#12
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#12
(Original post by XTinaA)
Well it is to our physicist brethren.
HAHA, imagine if we could go and watch Maths, live! :rolleyes: (Maybe not)
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makesomenoise
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#13
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#13
(Original post by bono)
ooooo, what is that fancy sin thingy?!
:rolleyes: <inhales>

The sine function is the ratio between the <rambles>
But as they say, you don't need to know how it works, you need to know how to work it...
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username9816
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(Original post by Nylex)
?
I was jokingly emphasizing how I wouldn't have a clue where to start.
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username9816
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#15
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#15
(Original post by XTinaA)
:rolleyes: <inhales>

The sine function is the ratio between the <rambles>
But as they say, you don't need to know how it works, you need to know how to work it...
I know what sin is Juwel, I do A-Level Maths.
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makesomenoise
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(Original post by bono)
I know what sin is Juwel, I do A-Level Maths.
I thought you'd need to study religion to know about sin...
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Fermat
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#17
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#17
(Original post by RAHAYDENUK)
Quote:
--------------------------------------------------------------------------------
Originally Posted by XTinaA
This won't by chance have anything to do with the Maclaurin approximation? Or am I way off track?
--------------------------------------------------------------------------------

Perhaps, as I say I've not done it!
If it's an approximation it's certainly accurate enough!
I checked it out for n=2 and got the lhs=rhs to an acuracy of 11 dp!
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theone
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#18
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#18
(Original post by bono)
I'll let "theone" battle this one.
I've only just looked at this, but have you tried induction?
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theone
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#19
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I take that back it isn't going to work too obviously. I'll think about it
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username9816
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#20
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#20
(Original post by theone)
I've only just looked at this, but have you tried induction?
P1, P2 and M1 on AQA B isn't enough to tackle this one.
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