#1
A's age is equal to the sum of the ages of B and C. Ten years ago A was twice as old as B. Show that 10 years hence A will be twice as old as C.
0
#2
Factorize: x47x2y2 + y4
0
8 years ago
#3
Hang on, do you want us to answer these or John, because you're putting it in the Q and A section...?
0
8 years ago
#4
Let , . Does that help?
0
#5
you may like to play around with 7x2y2.

check out if it reveals a hidden pattern
1
#6
(Original post by BlueSam3)
Let , . Does that help?
it certainly can
0
8 years ago
#7
(Original post by shubhro)
Factorize: x47x2y2 + y4
Surely this will NOT factorise.
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#8
(x4 + y4)– 7x2y2

what would you need to make (x4 + y4) into a perfect square.
0
8 years ago
#9
(Original post by brianeverit)
Surely this will NOT factorise.
It will. Surprisingly nicely, actually.
0
8 years ago
#10
(Original post by brianeverit)
Surely this will NOT factorise.
If you WolframAlpha that **** you'll find it does indeed factorise.
1
#11
0
8 years ago
#12
Why is this no longer in 'Ask John Bentley?'
0
#13
if you are still missing it by a whisker, may be you could take a look at the answer

0
#14
a number when divided by 123 leaves a remainder of 89. what is the remainder when it is divided by 41?
1
#15
how to solve this quadratic equation

Solve for x:

x2/3 + 3/ x2 = 5(x/3 – 1/x)
0
8 years ago
#16
267?
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8 years ago
#17
Let the nunber be N.
Then N = (123k) + 89 for some k.

Now divide by 41.
0
8 years ago
#18
If you expand the brackets and multiply through by 3x2, you will find yourself with a quartic not a quadratic.

That's all I have to contribute I'm afraid.
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8 years ago
#19
(Original post by BlueSam3)
It will. Surprisingly nicely, actually.
Of course, a senior moment there. I was just thinking of it as a quadratic in x^2 and y^2. Thanks for poinbt5ing it out.
0
8 years ago
#20
(Original post by Exon)
If you expand the brackets and multiply through by 3x2, you will find yourself with a quartic not a quadratic.

That's all I have to contribute I'm afraid.
The quartic is quite easily solved using the factor theorem.
0
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