Shubhro's questions thread

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shubhro
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#1
Report Thread starter 8 years ago
#1
A's age is equal to the sum of the ages of B and C. Ten years ago A was twice as old as B. Show that 10 years hence A will be twice as old as C.
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shubhro
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#2
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#2
Factorize: x47x2y2 + y4
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Plantagenet Crown
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#3
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#3
Hang on, do you want us to answer these or John, because you're putting it in the Q and A section...?
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BlueSam3
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#4
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#4
Let a = x^2, b = y^2. Does that help?
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shubhro
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#5
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#5
you may like to play around with 7x2y2.

check out if it reveals a hidden pattern
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shubhro
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#6
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#6
(Original post by BlueSam3)
Let a = x^2, b = y^2. Does that help?
it certainly can
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brianeverit
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#7
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#7
(Original post by shubhro)
Factorize: x47x2y2 + y4
Surely this will NOT factorise.
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shubhro
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#8
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#8
(x4 + y4)– 7x2y2

what would you need to make (x4 + y4) into a perfect square.
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BlueSam3
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#9
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#9
(Original post by brianeverit)
Surely this will NOT factorise.
It will. Surprisingly nicely, actually.
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contrapositive
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#10
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#10
(Original post by brianeverit)
Surely this will NOT factorise.
If you WolframAlpha that **** you'll find it does indeed factorise.
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shubhro
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#11
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#11
add and subtract 2x2y2
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contrapositive
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#12
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#12
Why is this no longer in 'Ask John Bentley?'
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shubhro
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#13
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#13
if you are still missing it by a whisker, may be you could take a look at the answer

http://ipm-mtse-olympiad-state-schol...torize_24.html
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shubhro
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#14
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#14
a number when divided by 123 leaves a remainder of 89. what is the remainder when it is divided by 41?
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shubhro
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#15
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#15
how to solve this quadratic equation

Solve for x:

x2/3 + 3/ x2 = 5(x/3 – 1/x)
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Hamushte
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#16
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#16
267?
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Matureb
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#17
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#17
Let the nunber be N.
Then N = (123k) + 89 for some k.

Now divide by 41.
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Exon
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#18
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#18
If you expand the brackets and multiply through by 3x2, you will find yourself with a quartic not a quadratic.

That's all I have to contribute I'm afraid.
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brianeverit
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#19
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#19
(Original post by BlueSam3)
It will. Surprisingly nicely, actually.
Of course, a senior moment there. I was just thinking of it as a quadratic in x^2 and y^2. Thanks for poinbt5ing it out.
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brianeverit
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#20
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#20
(Original post by Exon)
If you expand the brackets and multiply through by 3x2, you will find yourself with a quartic not a quadratic.

That's all I have to contribute I'm afraid.
The quartic is quite easily solved using the factor theorem.
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