Quantum Physics Questions :) Pls Help

Hey there,

Can someone help me please?

In the process of beta (-) decay an anti-neutrino is also realeased.

(i) Give an equation for this decay. (I HAVE DONE THIS AND PUT: )
n ----) p+ e(-) + ^-ve (anti-neutrino)

(ii) State and explain which conversation law may be used to show that it is an anti-neutrino rather than a neutrino that is released.

Please help me on (ii)

So in particle physics, the lepton number is conserved in a reaction. You can treat this number a bit like charge, because the units you will deal with here will be +1, 0 or -1.

All non-lepton (e.g. protons) particles have a lepton number of 0.
An electron has a lepton number of +1 because it is a lepton
An anti-neutrino has a lepton number of -1 because it is an anti-lepton.

Now, in your equation the Left Hand Side (LHS) has a lepton number of 0 because a neutron is not a lepton. Therefore...