find x which allows this inequality to hold:
So I thought since, we don't know if x is negative or positive create 2 cases. Case 1) where x is negative and therefore x+2x^2-x^3<2, and solve
or case 2) where x is positive and therefore x+2x^2-x^3>2
Then working out the solutions to each and finding which set of x values satisfy the equation?
If you can't help me with the actual equation, please let me know if my idea seems sensible or if it is flawed. Thanks!
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A tough inequality question! watch
- Thread Starter
- 07-10-2013 19:44
- Study Helper
- 07-10-2013 19:52
The cubic has easy roots.