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# C3 help differentiation watch

1. Find dy/dx in terms of y

x= 1/y - 1/y^2

x= (y^-1) - (y^-2)

dx/dy = (-y^-2) + (2y^-3)

Don't what to do from here?
2. (Original post by Vorsah)
Find dy/dx in terms of y

x= 1/y - 1/y^2

x= (y^-1) - (y^-2)

dx/dy = (-y^-2) + (2y^-3)

Don't what to do from here?
Find the reciprocal? You might want to form a single fraction first.
3. (Original post by Mr M)
Find the reciprocal? You might want to form a single fraction first.
Thanks
4. (Original post by Vorsah)
Thanks
Have you managed to do this?

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Updated: October 8, 2013
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