CORE 3-Differentiation
To differentiate:
y=3/(4+ln(2x-1))
Do I use the quotient rule?
Where am I going wrong here?
dy/dx= 4+ln(2x-1).0 - 3(2/(2x-1)) / (4+ln(2x-1))2
= -6(2x-1)-1 / (4+ln(2x-1))2
Is this correct? And can it be simplified any further?
y=3/(4+ln(2x-1))
Do I use the quotient rule?
Where am I going wrong here?
dy/dx= 4+ln(2x-1).0 - 3(2/(2x-1)) / (4+ln(2x-1))2
= -6(2x-1)-1 / (4+ln(2x-1))2
Is this correct? And can it be simplified any further?
Original post by Hasufel
use: and sub u=(4+ln(2x-1)) then use chain
but yes - you are correct! (can`t be simplified)
but yes - you are correct! (can`t be simplified)
So is my answer not correct?
Original post by Hasufel
use: and sub u=(4+ln(2x-1)) then use chain
but yes - you are correct! (can`t be simplified)
but yes - you are correct! (can`t be simplified)
Original post by Primrose96
So is my answer not correct?
See above ^
Original post by Primrose96
To differentiate:
y=3/(4+ln(2x-1))
Do I use the quotient rule?
Where am I going wrong here?
dy/dx= 4+ln(2x-1).0 - 3(2/(2x-1)) / (4+ln(2x-1))2
= -6(2x-1)-1 / (4+ln(2x-1))2
Is this correct? And can it be simplified any further?
y=3/(4+ln(2x-1))
Do I use the quotient rule?
Where am I going wrong here?
dy/dx= 4+ln(2x-1).0 - 3(2/(2x-1)) / (4+ln(2x-1))2
= -6(2x-1)-1 / (4+ln(2x-1))2
Is this correct? And can it be simplified any further?
Your first line of working is correct.
The problem is this: how did the negative power suddenly appear in the 2nd line of working?
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