For a homework we've been set to do the following dot and cross diagrams for dative covalent bonds;
H2O -> H+ F3N -> BF3 Cl- -> AlCl3
This might seem like a really simple and stupid thing but that's often the things that get to me in the world of chemistry.. Does anyone know how to do these?
For a homework we've been set to do the following dot and cross diagrams for dative covalent bonds;
H2O -> H+ F3N -> BF3 Cl- -> AlCl3
This might seem like a really simple and stupid thing but that's often the things that get to me in the world of chemistry.. Does anyone know how to do these?
Thank you
The bond is exactly the same for all the bonds in the oxonium and the AlCl4.... all 4 bonds are completely equivalent...... thats the problem with dative bonding, it's a simple model for picturing bonding in some molecules but gives a totally twisted picture in these sort of examples. It's OK for the nitrogen and boron example....
Just draw out the molecules and put in the bonds. Then add 2 electrons for each bond as per usual. You'll end up with a formal positive charge on the O and a negative on the Al. For the N and B molecule there is a positive on the nitrogen and a negative on the boron.