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# Trigonometrical equation 2 watch

1. Solve the following for 0° ≤ x ≤ 360°:
5secx +3cosecx = 0
I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
2. (Original post by ZoeM0410)
Solve the following for 0° ≤ x ≤ 360°:
5secx +3cosecx = 0
I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
you just have to rearange the equation and use
secx=1/cosx cosecx=1/sinx and tanx=(sinx)/(cosx)
3. (Original post by ZoeM0410)
Solve the following for 0° ≤ x ≤ 360°:
5secx +3cosecx = 0
I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
Have you considered the following?

4. (Original post by ZoeM0410)
Solve the following for 0° ≤ x ≤ 360°:
5secx +3cosecx = 0
I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
So
5/cosx = - 3/sinx
I'd Multiply through by sinx.
5sinx / cosx = -3
Notice that sinx/cosx = tanx

Are you ok from here?
5. Thanks ! That really helps, I've got it now !

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