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    Solve the following for 0° ≤ x ≤ 360°:
    5secx +3cosecx = 0
    I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
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    (Original post by ZoeM0410)
    Solve the following for 0° ≤ x ≤ 360°:
    5secx +3cosecx = 0
    I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
    you just have to rearange the equation and use
    secx=1/cosx cosecx=1/sinx and tanx=(sinx)/(cosx)
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    (Original post by ZoeM0410)
    Solve the following for 0° ≤ x ≤ 360°:
    5secx +3cosecx = 0
    I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
    Have you considered the following?

    \sec x = \frac{1}{\cos x}

    \csc x = \frac{1}{\sin x}
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    (Original post by ZoeM0410)
    Solve the following for 0° ≤ x ≤ 360°:
    5secx +3cosecx = 0
    I've tried substituting things but I can't seem to get the two parts into the same form, which I'm assuming you have to do? Any help?
    So
    5/cosx = - 3/sinx
    I'd Multiply through by sinx.
    5sinx / cosx = -3
    Notice that sinx/cosx = tanx

    Are you ok from here?
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    Thanks ! That really helps, I've got it now !
 
 
 
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