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    how do you find the coordinates of the vertex in the equation x2​+10x+19?
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    (Original post by MSB47)
    how do you find the coordinates of the vertex in the equation x2​+10x+19?
    Either differentiate to find the turning point or complete the square.
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    Do you know how to differentiate, or have you not got to calculus yet?
    (This might affect your approach to the question.)
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    (Original post by placenta medicae talpae)
    Do you know how to differentiate, or have you not got to calculus yet?
    (This might affect your approach to the question.)
    i have just started calculus and been introduced to the dy/dx formula
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    (Original post by MSB47)
    i have just started calculus and been introduced to the dy/dx formula
    Cool: calculus will make this nice and simple for you

    You want to find a point where your function, call it f, has gradient 0.
    You can do this by differentiating f(x) and setting the result to equal 0.
    This will happen at precisely one x-value (as is the case for any parabola).
    So all you need to do is crunch the numbers
 
 
 
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