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    Need help with Q14 A

    Using product rule I got dy/dx= 3(x+1)^2(2x-1)^4 + 8(2x-1)^3(x+1)^3

    Need help from here
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    (Original post by Vorsah)
    Need help with Q14 A

    Using product rule I got dy/dx= 3(x+1)^2(2x-1)^4 + 8(2x-1)^3(x+1)^3

    Need help from here
    dy/dx = v[du/dx] - u[dv/dx]
    =[(2x-1)^4][3(x+1)^2][1] - [(x+1)^3][4(2x-1)^3][2]
    =3[(x+1)^2][(2x-1)^4] - 8[(x+1)^3][(2x-1)^3]

    Try factorising as (x+1)^2 is a common factor as well as (2x-1)^3
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    (Original post by krisshP)
    dy/dx = v[du/dx] - u[dv/dx]
    =[(2x-1)^4][3(x+1)^2][1] - [(x+1)^3][4(2x-1)^3][2]
    =3[(x+1)^2][(2x-1)^4] - 8[(x+1)^3][(2x-1)^3]

    Try factorising as (x+1)^2 is a common factor as well as (2x-1)^3
    Thanks
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    (Original post by Vorsah)
    Thanks
    You should get this
    Name:  1381695354585.jpg
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Size:  30.1 KB


    Then you can just expand out the stuff in [......] and simplify
 
 
 
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