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Physics A2 Mechanics Circular Velocity watch

1. Communications satellites orbit above the equator in orbits of radius 4.24x107 with a period of 24 hours. Calculate the angular velocity of a communications satellite and the centripetal acceleration that it experiences.

So,

Right?
2. Well, that's orbital speed. You want angular velocity.
do you know a formula that connects the two?
3. (Original post by Stonebridge)
Well, that's orbital speed. You want angular velocity.
do you know a formula that connects the two?
Got that one...
So, a racing car of mass 500kg goes around a cirrcular racetrack with a diameter 350m at a speed of 150km per hour. What is the centripetal force acting on the car?

I do:

4. (Original post by halpme)
Got that one...
So, a racing car of mass 500kg goes around a cirrcular racetrack with a diameter 350m at a speed of 150km per hour. What is the centripetal force acting on the car?

I do:

What is the 3.6?

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5. (Original post by Qari)
What is the 3.6?

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I was wondering that, and also you measure in metres per second so convert 150kmh^-1 to ms^-1 to use in the equation.
6. (Original post by Qari)
What is the 3.6?

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(Original post by The_Top_Hat)
I was wondering that, and also you measure in metres per second so convert 150kmh^-1 to ms^-1 to use in the equation.

3.6 converts it to m/s...
7. (Original post by halpme)
3.6 converts it to m/s...
Ah ok, didn't look to figure it out. It's just most people when they have some sort of problem post their bare basic working so people can check first of all to make sure they didn't make an elementary error. I just didn't see it when I glanced at it

I've done the question now properly I have looked at it and I agree with your answer. Must be a mistake in the mark scheme.
8. (Original post by halpme)
3.6 converts it to m/s...
The fracs confuse me

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9. (Original post by Qari)
The fracs confuse me

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150kmh -> Xms

150km = 150000m

hour = 60 (minutes) x 60 (Seconds)

so 150kmh = (150000)/(60x60)ms^-1

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Updated: October 14, 2013
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