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Percentage Yield HW Help?

Hi;

Well, I am stuck on this percentage yield question, I am not used to using oxidized products, can anyone provide a step by step guide on how to calculate please? =l

EDIT:
I keep getting an answer of 66.9%

Working - 2.4/116 = moles of original reactants
1.8/130 = Moles of products

Reactants/products * 100 = 66.9%. =l
(edited 10 years ago)
Question 5.PNG342.6KB
Original post by SomeGuy21
66.9%. =l

That is the right answer.

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