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    Can someone explain how they got the expression N = Pcos(Theta)

    Isn't it cos(theta)= P / N

    so that

    N = P / cos(theta) ?



    thanks
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    (Original post by crescendo7)
    http://postimg.org/image/yniz5pfab/

    Can someone explain how they got the expression N = Pcos(Theta)

    Isn't it cos(theta)= P / N

    so that

    N = P / cos(theta) ?



    thanks


    No

    The force that you are resolving is always the hypotenuse
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    (Original post by TenOfThem)
    The force that you are resolving is always the hypotenuse
    Why would it be wrong if this was not the case e.g if N was the hypotenuse
    and P was the adjacent side
    What would be wrong with the right angled triangle
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    (Original post by crescendo7)
    Why would it be wrong if this was not the case e.g if N was the hypotenuse
    and P was the adjacent side
    What would be wrong with the right angled triangle
    You resolve a force into 2 perpendicular directions - so the resolved directions must have a right angle between them - therefore the force has to be the hypotenuse
 
 
 
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