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# Simple trig question watch

1. http://postimg.org/image/yniz5pfab/

Can someone explain how they got the expression N = Pcos(Theta)

Isn't it cos(theta)= P / N

so that

N = P / cos(theta) ?

thanks
2. (Original post by crescendo7)
http://postimg.org/image/yniz5pfab/

Can someone explain how they got the expression N = Pcos(Theta)

Isn't it cos(theta)= P / N

so that

N = P / cos(theta) ?

thanks

No

The force that you are resolving is always the hypotenuse
3. (Original post by TenOfThem)
The force that you are resolving is always the hypotenuse
Why would it be wrong if this was not the case e.g if N was the hypotenuse
and P was the adjacent side
What would be wrong with the right angled triangle
4. (Original post by crescendo7)
Why would it be wrong if this was not the case e.g if N was the hypotenuse
and P was the adjacent side
What would be wrong with the right angled triangle
You resolve a force into 2 perpendicular directions - so the resolved directions must have a right angle between them - therefore the force has to be the hypotenuse

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