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# Coordinate Geometry watch

1. Exercise 5C - Question 8 - Edexcel Core 1
Question States: The line p has gradient 2/3 and passes through the points (6, - 12). The line q has gradient -1 and passes through the point (5,5). The line p meets the y-axis at A and the line q meets the x-axis at point B. Work out the gradient of the line joining the points and A and B.

This is what I've gotten so far...

(6,-12) where m=2/3, working out the equation of the line I got: Y=2/3x-16 (p)

(5,5) where m= -1, working out the equation of the line I got: Y=-x+10 (q)

Now it states the P crosses the Y-axis so therefore sub. x = 0 in order to find the Y value, I got Y = -16 , therefore in coordinate terms we get (0,-16).

For q => It states the q meets at x-axis, therefore sub. Y = 0 to get x value; for which I got x = 10; therefore in coordinate value I got (10,0)

Now to find the gradient of which the line joins Points A = (0,-16) and B = (10,0) for which the equation to find the gradient of any to coordinate points we do y2-y1/x2-x1 , right? so what I then did was 0--(-- = +) 16 = 16. And then 10-0 = 10? I got m=1.6? Edexcel put 8/5. Which is the same as 1.6 fair enough... but solution bank did this :-16-0 = - 16 and then did 0-10; is this wrong mathematically? As the equation does State y2-y1/x2-x1
Even though they got the same answer? Or am I wrong, I don't know...
2. (Original post by Cool-Light)
Exercise 5C - Question 8 - Edexcel Core 1
Question States: The line p has gradient 2/3 and passes through the points (6, - 12). The line q has gradient -1 and passes through the point (5,5). The line p meets the y-axis at A and the line q meets the x-axis at point B. Work out the gradient of the line joining the points and A and B.

This is what I've gotten so far...

(6,-12) where m=2/3, working out the equation of the line I got: Y=2/3x-16 (p)

(5,5) where m= -1, working out the equation of the line I got: Y=-x+10 (q)

Now it states the P crosses the Y-axis so therefore sub. x = 0 in order to find the Y value, I got Y = -16 , therefore in coordinate terms we get (0,-16).

For q => It states the q meets at x-axis, therefore sub. Y = 0 to get x value; for which I got x = 10; therefore in coordinate value I got (10,0)

Now to find the gradient of which the line joins Points A = (0,-16) and B = (10,0) for which the equation to find the gradient of any to coordinate points we do y2-y1/x2-x1 , right? so what I then did was 0--(-- = +) 16 = 16. And then 10-0 = 10? I got m=1.6? Edexcel put 8/5. Which is the same as 1.6 fair enough... but solution bank did this :-16-0 = - 16 and then did 0-10; is this wrong mathematically? As the equation does State y2-y1/x2-x1
Even though they got the same answer? Or am I wrong, I don't know...
Are you serious

I read all of that and you want to know if your order of co-ordinates is better than the one chosen in exam solutions

If you are looking for the gradient of a line either end can be
3. (Original post by TenOfThem)
Are you serious

and you want to know if your order of co-ordinates is better than the one chosen in exam solutions

If you are looking for the gradient of a line either end can be
Lol.
4. Sorry bro, no hard feelings and I just wanted to ensure that I wasn't wrong
5. (Original post by Cool-Light)
Sorry bro, no hard feelings and I just wanted to ensure that I wasn't wrong
She's female.
Also, this query didn't exactly warrant a thread...
For trivial questions such as this, please post in the Alevel maths thread in the future please

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Updated: November 15, 2013
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