You are Here: Home >< Maths

# Quotient rule question watch

1. I just...

Posted from TSR Mobile
Attached Images

I just...

Posted from TSR Mobile
3. Can't do it

Posted from TSR Mobile
Can't do it

Posted from TSR Mobile
put dy/dx=0 in the usual way, noting that we cannot have x=0
Can't do it

Posted from TSR Mobile
Put the x^-1 in the denominator so that you have x^7

Factorise the numerator and cancel appropriately

Put the fraction =0

Remember that if a fraction is 0 then it is the numerator that =0
6. (Original post by TenOfThem)
Put the x^-1 in the denominator so that you have x^7

Factorise the numerator and cancel appropriately

Put the fraction =0

Remember that if a fraction is 0 then it is the numerator that =0

Posted from TSR Mobile
Attached Images

7. the denominator is x^7

it would be x^(-7) if you have it in the numerator
8. (Original post by TenOfThem)
the denominator is x^7

it would be x^(-7) if you have it in the numerator
X^-1 ÷ X^6?

Posted from TSR Mobile
X^-1 ÷ X^6?

Posted from TSR Mobile
yes - in the numerator

but x^6 x x^1 if in the denominator
10. (Original post by TenOfThem)
yes - in the numerator

but x^6 x x^1 if in the denominator
OK but I don't know how to go on from there. There answer is 1/3 e^-1

Posted from TSR Mobile
11. (Original post by TenOfThem)
yes - in the numerator

but x^6 x x^1 if in the denominator

Posted from TSR Mobile
Attached Images

12. When you cancel x^3 you are left with x^4 in the denominator

Again though, the numerator = 0
13. (Original post by TenOfThem)
When you cancel x^3 you are left with x^4 in the denominator

Again though, the numerator = 0
Why is the numerator 0

Posted from TSR Mobile
14. (Original post by TenOfThem)
When you cancel x^3 you are left with x^4 in the denominator

Again though, the numerator = 0
I didn't get e^-1

Posted from TSR Mobile
Attached Images

15. You have done the last parts wrong. Personally I would divide the equation through by 3 to get:

Then take e of both sides, which would give you:

Or:

So,

Then sub the back into the original equation
16. (Original post by Phichi)
You have done the last parts wrong. Personally I would divide the equation through by 3 to get:

Then take e of both sides, which would give you:

Or:

So,

Then sub the back into the original equation
I don't see how that would get you 1/3 x e^-1

Posted from TSR Mobile
I don't see how that would get you 1/3 x e^-1

Posted from TSR Mobile
We've found that:

Sub this into the original equation and find the value.

So:

18. (Original post by Phichi)
We've found that:

Sub this into the original equation and find the value.

So:

I see now. Thanks dude

Posted from TSR Mobile

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: November 19, 2013
Today on TSR

### University open days

Wed, 21 Nov '18
• Buckinghamshire New University
Wed, 21 Nov '18
• Heriot-Watt University
Wed, 21 Nov '18
Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE