C1 urgent help Watch

M.M.HUSSAIN
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Hi,

I have a question:

using the discriminant show that the equation x^2-4x+5=0 has no real roots

i used b^2-4ac but i can't show it has no real roots

Thank you
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TenOfThem
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(Original post by M.M.HUSSAIN)
Hi,

I have a question:

using the discriminant show that the equation x^2-4x+5=0 has no real roots

i used b^2-4ac but i can't show it has no real roots

Thank you
What did you get when you used b^2-4ac
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techno-thriller
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4^2-4x(1)(5)=16-20=-4 therefore no real roots. You just have to show that the number is negative.
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M.M.HUSSAIN
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(Original post by techno-thriller)
4^2-4x(1)(5)=16-20=-4 therefore no real roots. You just have to show that the number is negative.
oh right thanks
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TenOfThem
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(Original post by M.M.HUSSAIN)
oh right thanks
Do you understand why that works

After all, I assume that you got -4 but could not finish the question
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