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# Stoichiometry Calculating Volume HELP PLEASE!!! watch

1. 1. Magnesium reacts with oxygen to form magnesium oxide
2Mg(s) + O2 > 2MgO(s)
Calculate the volume of oxygen that would be required to react with 1.20g of magnesium.
(1mole of a gas has a volume of 24dm^3 under the conditions in this experiment)
2. The number of moles of oxygen gas needed can be found by comparing with the number of moles of Magnesium needed, so you need to work that out first, then by looking at their ratios in the equation will help find the moles of oxygen. Then Volume = mol x 24
3. (Original post by DDeeno)
1. Magnesium reacts with oxygen to form magnesium oxide
2Mg(s) + O2 > 2MgO(s)
Calculate the volume of oxygen that would be required to react with 1.20g of magnesium.
(1mole of a gas has a volume of 24dm^3 under the conditions in this experiment)
if you would still like help with this, I can make a video explaining how you can solve this question.

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Updated: January 18, 2014
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