# c3 - Algebraic DivisionWatch

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#1
4x4-3x3+3x+1/x2-1

I have no idea how to do this. Any Help?

Edit:
I get -3x^3 - -4x^2
But i'm not sure if you can do this.

0
5 years ago
#2
Long division.
0
5 years ago
#3
(Original post by ninuzu)
Long division.
This ^, do it
1
#4
Yeah but then I get -3x^3 - -4x^2
Which I think you can't do.

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0
5 years ago
#5
Algebraic long division. Remember you can write in 0x^3, 0x^2 etc terms if it you need to..
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#6
(Original post by ninuzu)
Long division.

Yeah but then I get -3x^3 - -4x^2

Which I think you can't do.

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5 years ago
#7
(Original post by Hedgehogkilla)

Yeah but then I get -3x^3 - -4x^2

Which I think you can't do.

Try and keep terms of the same order in the same columns, where you have -4x^2 write 0x^3 and shift the -4x^2 to the right.
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5 years ago
#8

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#9
(Original post by Liamnut)
Try and keep terms of the same order in the same columns, where you have -4x^2 write 0x^3 and shift the -4x^2 to the right.
Oh, ok. Thanks!
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#10
(Original post by ninuzu)

Thanks for helping!
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5 years ago
#11
(Original post by ninuzu)

I don't think that's correct. I get the remainder is 3.
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5 years ago
#12
(Original post by Liamnut)
I don't think that's correct. The remainder is 3.

x^2-1=(x-1)(x+1), Plug 1 in, you get 3 and plug -1 in and you get 3. This is also what I get when I do long division.
Oh s*** yeah I did it wrong it's been a while since I've done this stuff...
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#13
(Original post by Liamnut)
I don't think that's correct. I get the remainder is 3.
Can you please explain the mistake in the long division? I can't find it.
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5 years ago
#14
(Original post by Hedgehogkilla)
Can you please explain the mistake in the long division? I can't find it.
He shouldn't have brought the 1 down when he did. Also, the remainder is 5 not 3... (I wrote down 4x^4-3x^3+3x-1).
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#15
(Original post by Liamnut)
He shouldn't have brought the 1 down when he did. Also, the remainder is 5 not 3... (I wrote down 4x^4-3x^3+3x-1).
Cool. Cool, cool, cool.

Thanks for helping.
0
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