A level maths urgent help needed? Watch

KPfan
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The line L1 passes through point (9, -4) and has gradient 1/3. Find an equation for L1 in the form ax+by+c=0 where a, b and c are integers.
I think it is 1x-3y-12=0, is that right?

and the line L2 passes through the origin 0 and has gradient -2. The lines L1 and L2 intersect at the point P. Calculate the coordinates of P? How do I do that?
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benclarky
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nvm, realised im clueless on a level maths haha
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usycool1
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(Original post by KPfan)
The line L1 passes through point (9, -4) and has gradient 1/3. Find an equation for L1 in the form ax+by+c=0 where a, b and c are integers.
I think it is 1x-3y-12=0, is that right?
Not quite, it should be -21 at the end (you may have made a typo?).

and the line L2 passes through the origin 0 and has gradient -2. The lines L1 and L2 intersect at the point P. Calculate the coordinates of P? How do I do that?
Form an equation for L2, and then solve simultaneously.
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THEMathlete
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I got a diff. Answer for the equation of L1...


For the second part try solving the equations simultaneously. If L2 goes through the origin then the equation is y = -2x.

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President Snow
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First let's look at this part:

(Original post by KPfan)
The line L1 passes through point (9, -4) and has gradient 1/3. Find an equation for L1 in the form ax+by+c=0 where a, b and c are integers.
I think it is 1x-3y-12=0, is that right?
You're close, but it's not quite right. Please have another go, posting your working, and we'll correct you further from there.
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gdunne42
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(Original post by KPfan)
The line L1 passes through point (9, -4) and has gradient 1/3. Find an equation for L1 in the form ax+by+c=0 where a, b and c are integers.
I think it is 1x-3y-12=0, is that right?

and the line L2 passes through the origin 0 and has gradient -2. The lines L1 and L2 intersect at the point P. Calculate the coordinates of P? How do I do that?
Your equation isn't right.
Put x=9 and y=-4 into your equation and you will see it does not = 0

How did you work it out?

y - y1 = m(x - x1)

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